Make use of the property that sqrt(ab)=sqrt(a) x sqrt(b) and try to find an 'a' or 'b' that can be expressed as a whole number; these combinations of a square root and a coefficient are called surds.
e.g. In square root form, sqrt(18) = sqrt(9 x 2)= sqrt(9) x sqrt(2). This, in surd form, is 3 x sqrt(2).
Note that the property sqrt(ab) = sqrt(a) X sqrt(b) does not hold for negative radicands (imaginary numbers) unless negative roots are accounted for. For example, it is known that sqrt(-1) X sqrt(-1) = -1. The property mentioned above would imply that sqrt(-1) X sqrt(-1) = sqrt(-1 X (-1) = sqrt(1) which is only true if the square root of 1 is taken to be either 1 or -1.
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It might be best to answer this with an example. Look at the square root of 8. To simplify it we notice that 8 is 2x4 and that 4 is a perfect square. So we can simplify the square root by taking the 4 out of the radical sign and writing it as 2xsquare root of 2. Perhaps a better way to think of this is that is you have square root of a x square root of b, that is the square root of (ab). So if we have square root of 8 that is the same as square root of 4 x square root of 2 and square root of 4 is 2 so the answer is 2xsquare root of 2. In general, look for perfect squares and factor them out of the number so they can be removed from the square root.
The square roots of 13 cannot be simplified.
Replace the radical sign with the exponent 0.5. For example sqrt(7) = 70.5
You can add simplified square roots only if the radicals are the same and, in that case, you treat the radicals as you would treat a variable in algebra.For example, sqrt(18) + sqrt(50)= sqrt(9*2) + sqrt(25*2)= 3*sqrt(2) + 5*sqrt(2)= [3 + 5]*sqrt(2)= 8*sqrt(2)
All prime numbers have irrational number square roots, so if you try to find the square root of a non-perfect square number use them to simplify it. For example, ±√125 = ±√25*5 = ±5√5 (when you want to show both the square roots) √72 = √36*2 = 6√2 √-27 = √-9*3 = 3i√3
simplify the square root of 300 divided by the square root of 6