How do you simplify x2-9 over x2-6x plus 9?

Answer 1

First you distribute: x2-9 = (x-3)(x+3) and that is you numerator. Distribute x2-6x+9. Find two #'s that mult. to make 9 and add to make 6. 3x3=9 and 3+3=6. now you replace the 6x with -3x and -3x so rewrite the problem as x2-3x-3x+9 then you distribute x(x-3)-3(x-3) so x2-6x+9 becomes (x-3)(x-3) and that is your denominator.

Tharefore: (x-3)(x+3) over (x-3)(x-3)

then cross out like terms and your answer is

(x+3) over (x-3)