i have know idea sorry!
To solve the expression "5 ADD 1 MULTIPLY BY 10 BY 10," we first interpret it as ( (5 + 1) \times 10 \times 10 ). This simplifies to ( 6 \times 10 \times 10 = 6 \times 100 = 600 ). Therefore, the sum is 600.
To solve the expression (10 - 3 \times 3), we first perform the multiplication: (3 \times 3 = 9). Then, we subtract that result from 10: (10 - 9 = 1). Therefore, the answer is 1.
To solve ( 10C3 ), which represents the number of combinations of 10 items taken 3 at a time, you use the formula: [ nCr = \frac{n!}{r!(n-r)!} ] For ( 10C3 ), this becomes: [ 10C3 = \frac{10!}{3!(10-3)!} = \frac{10!}{3! \cdot 7!} ] Calculating this gives: [ = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = \frac{720}{6} = 120 ] Thus, ( 10C3 = 120 ).
you times somthing by 2 then somthing by 5 2*5 = 10 5*2 = 10
To solve ( 40 \times 10^2 ), first calculate ( 10^2 ), which equals 100. Then, multiply 40 by 100: ( 40 \times 100 = 4000 ). Thus, the answer is 4000.
To solve 10 1 3, you can multiply 10 times 1. This gives you a product of 10. Then multiply 10 times 3, so you will have an answer of 30.
Multiply -10 times 12 = -120
To use the distributive property to solve (10 \times 147), you can break down 147 into two simpler components, such as (100 + 40 + 7). Then, apply the distributive property: [ 10 \times 147 = 10 \times (100 + 40 + 7) = (10 \times 100) + (10 \times 40) + (10 \times 7). ] Calculating each term gives (1000 + 400 + 70 = 1470), so (10 \times 147 = 1470).
To solve the equation (80 \times 7 = s \times 10), follow these steps: **Calculate (80 \times 7)**: [ 80 \times 7 = 560 ] **Set up the equation**: [ 560 = s \times 10 ] **Solve for (s)** by dividing both sides by 10: [ s = \frac{560}{10} = 56 ] Therefore, the value of (s) is (56).
you divide whatever the number is by 10 then you times it by thirty
Three times a number is 10 less five times the number can be put in the form of an equation that looks like this: 3x = 5x-10. Now just solve for x...
MY 03 ALTIMA HAD THE SAME PROBLEM I HAD TO REPLACE THE CAM SENSORS AND THE PROBLEM WAS SOLVE
To solve ( 10C3 ), which represents the number of combinations of 10 items taken 3 at a time, you use the formula: [ nCr = \frac{n!}{r!(n-r)!} ] For ( 10C3 ), this becomes: [ 10C3 = \frac{10!}{3!(10-3)!} = \frac{10!}{3! \cdot 7!} ] Calculating this gives: [ = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = \frac{720}{6} = 120 ] Thus, ( 10C3 = 120 ).
To solve this level once type "answer" in your notepad. To solve twice type "the answer" in your notepad. To solve three times type "el answer" in your note pad and you will earn a gold star in this level.
7a=2(-10)........................................answer is 20/7
0.4/10 = 0.04
you times somthing by 2 then somthing by 5 2*5 = 10 5*2 = 10