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How to solve 10 1 3-?

To solve 10 1 3, you can multiply 10 times 1. This gives you a product of 10. Then multiply 10 times 3, so you will have an answer of 30.


How do you solve -10 x 12?

Multiply -10 times 12 = -120


How do you use the distributive property to solve 10 times 147?

To use the distributive property to solve (10 \times 147), you can break down 147 into two simpler components, such as (100 + 40 + 7). Then, apply the distributive property: [ 10 \times 147 = 10 \times (100 + 40 + 7) = (10 \times 100) + (10 \times 40) + (10 \times 7). ] Calculating each term gives (1000 + 400 + 70 = 1470), so (10 \times 147 = 1470).


80×7=s×10?

To solve the equation (80 \times 7 = s \times 10), follow these steps: **Calculate (80 \times 7)**: [ 80 \times 7 = 560 ] **Set up the equation**: [ 560 = s \times 10 ] **Solve for (s)** by dividing both sides by 10: [ s = \frac{560}{10} = 56 ] Therefore, the value of (s) is (56).


What is the sum of 5 ADD 1 MULTIPLY BY10 BY 10?

To solve the expression "5 ADD 1 MULTIPLY BY 10 BY 10," we first interpret it as ( (5 + 1) \times 10 \times 10 ). This simplifies to ( 6 \times 10 \times 10 = 6 \times 100 = 600 ). Therefore, the sum is 600.


How do you solve 30 percent of 2027?

you divide whatever the number is by 10 then you times it by thirty


What is 10-3times 3?

To solve the expression (10 - 3 \times 3), we first perform the multiplication: (3 \times 3 = 9). Then, we subtract that result from 10: (10 - 9 = 1). Therefore, the answer is 1.


Three times a number is 10 less five times the number?

Three times a number is 10 less five times the number can be put in the form of an equation that looks like this: 3x = 5x-10. Now just solve for x...


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How do you solve 10C3?

To solve ( 10C3 ), which represents the number of combinations of 10 items taken 3 at a time, you use the formula: [ nCr = \frac{n!}{r!(n-r)!} ] For ( 10C3 ), this becomes: [ 10C3 = \frac{10!}{3!(10-3)!} = \frac{10!}{3! \cdot 7!} ] Calculating this gives: [ = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = \frac{720}{6} = 120 ] Thus, ( 10C3 = 120 ).


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How do you solve x 2 and x 5?

you times somthing by 2 then somthing by 5 2*5 = 10 5*2 = 10