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To solve ( 10C3 ), which represents the number of combinations of 10 items taken 3 at a time, you use the formula:
[ nCr = \frac{n!}{r!(n-r)!} ]
For ( 10C3 ), this becomes:
[ 10C3 = \frac{10!}{3!(10-3)!} = \frac{10!}{3! \cdot 7!} ]
Calculating this gives:
[ = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = \frac{720}{6} = 120 ]
Thus, ( 10C3 = 120 ).
What else can I help you with?
What is the answer to 10c3 using pascals triangle?
To find (10C3) using Pascal's Triangle, locate the row corresponding to (n=10). The entries in this row represent the binomial coefficients for (n=10). The third entry (starting from (0)) in this row corresponds to (10C3), which is (120). Thus, (10C3 = 120).
How many three digit combinations 000 999 are there without repeating the same number twice?
There are 10C3 = 10*9*8/(3*2*1) = 120 combinations.
You flip a fair coin 10 times What is the probability that it lands on heads exactly 3 times?
It is 10C3*(1/2)10 = 10*9*8/(3*2*1)*(1/1024) = 0.1172, approx.
What is the verb of solve?
its solve easy
How do you solve problums?
to solve them you have to do stagigys
What is the answer to 10c3 using pascals triangle?
To find (10C3) using Pascal's Triangle, locate the row corresponding to (n=10). The entries in this row represent the binomial coefficients for (n=10). The third entry (starting from (0)) in this row corresponds to (10C3), which is (120). Thus, (10C3 = 120).
What is the value of 10c3?
The answer depends on the value of c!
How many 3 combinations are in 10 numbers?
There are: 10C3 = 120
How many three digit combinations 000 999 are there without repeating the same number twice?
There are 10C3 = 10*9*8/(3*2*1) = 120 combinations.
If you flip 10 pennies all at the same time what is the probability that exactly 3 will come up heads and 7 will come up tail?
10C3(0.5)^10
You flip a fair coin 10 times What is the probability that it lands on heads exactly 3 times?
It is 10C3*(1/2)10 = 10*9*8/(3*2*1)*(1/1024) = 0.1172, approx.
What is a nickname for solvent?
solve solve solve
How do you simplify exponents?
Rules for exponents. a^(n) X a^(m) = a^(n+m) a^(n) / a^(m) = a^(n-m) (a^(n))^(m) = a^(nm) In all cases the coefficient 'a' MUST be the same value in all cases. Also square root(a) = a^(1/2) cube root (a) = a^(1/3) nth root (a) = a^(1/n) Finally a^(-1/n) = 1/a(n)
How do you solve a diagonal?
you solve it
What is the verb of solve?
its solve easy
How do you solve problums?
to solve them you have to do stagigys
How do you solve combination circuits?
Generally,1. Convert parallel branches into series equivalents2. Solve for the total resistance3. Solve for individual voltages4. Solve for individual currents5. Solve for power
