Well if you mean you have to solve w^3+27 then I guess make it = 0 then solve it w^3+27=0 -27 w^3=27 3rd root w=-3 ~¤~Amy~¤~
It is: 2/3 times 27 = 18
Set up the equation and solve: -27 = 8x - 5x (next simplify by subtracting 5x from 8x)) -27 = 3x (next divide both sides of the equation by 3) -27/3 = 3x/3 (next simplify and solve) -9 = x
Set up the equation and solve: -27 = 8x - 5x (next simplify by subtracting 5x from 8x)) -27 = 3x (next divide both sides of the equation by 3) -27/3 = 3x/3 (next simplify and solve) -9 = x
(-3)x(-3)2 =(-3)(9)=-27
Well if you mean you have to solve w^3+27 then I guess make it = 0 then solve it w^3+27=0 -27 w^3=27 3rd root w=-3 ~¤~Amy~¤~
It is: 2/3 times 27 = 18
Set up the equation and solve: -27 = 8x - 5x (next simplify by subtracting 5x from 8x)) -27 = 3x (next divide both sides of the equation by 3) -27/3 = 3x/3 (next simplify and solve) -9 = x
3 by 3
Set up the equation and solve: -27 = 8x - 5x (next simplify by subtracting 5x from 8x)) -27 = 3x (next divide both sides of the equation by 3) -27/3 = 3x/3 (next simplify and solve) -9 = x
Set up the equation and solve: -27 = 8x - 5x (next simplify by subtracting 5x from 8x)) -27 = 3x (next divide both sides of the equation by 3) -27/3 = 3x/3 (next simplify and solve) -9 = x
(-3)x(-3)2 =(-3)(9)=-27
Divide by 8 and you get 3 with 3 left over. so 27 is written as 33 in octal (base-8).
3/9 = x/81 x = 27 So: 3/9 = 27/81
27x-3=105 27x =105+3 27x = 108 27x/27=108/27 x= 4
Given 3x = 1/27 divide both sides by 3: 3x ÷ 3 = 1/27 ÷ 3 → x = 1/27 ÷ 3/1 → x = 1/27 × 1/3 → x = 1/(27×3) → x = 1/81 Dividing by 3 is the same as multiplying by the reciprocal of 3, namely 1/3.
How to solve this problem v427