To solve the equation (2^x = 3), take the logarithm of both sides. This can be done using either natural logarithm (ln) or common logarithm (log):
[ x = \log_2(3) = \frac{\log(3)}{\log(2)} ]
This gives you the value of (x) in terms of logarithms. You can then use a calculator to find the numerical value if needed.
3
To solve -5+2+(-3), start by adding -5 and 2 together which equals -3. Then, add -3 to -3 which gives you a final answer of -6.
3 raised to negative 2 would be -9 plus 6 to the negative 1 which is -6 so -9+-6=-15
To find what to the 8th power equals 64, we can express 64 as a power of 2: (64 = 2^6). Therefore, we need to solve the equation (x^8 = 2^6). Taking the 8th root of both sides gives (x = 2^{6/8} = 2^{3/4}). Thus, (2^{3/4}) is the number that, when raised to the 8th power, equals 64.
7
-2 plus 5 equals +3
3
3
3
3
You would do it it by oppisites. 3+2+4=9 which equals C.
x=-2
8
To solve -5+2+(-3), start by adding -5 and 2 together which equals -3. Then, add -3 to -3 which gives you a final answer of -6.
-2+5=3
3 raised to negative 2 would be -9 plus 6 to the negative 1 which is -6 so -9+-6=-15
To find what to the 8th power equals 64, we can express 64 as a power of 2: (64 = 2^6). Therefore, we need to solve the equation (x^8 = 2^6). Taking the 8th root of both sides gives (x = 2^{6/8} = 2^{3/4}). Thus, (2^{3/4}) is the number that, when raised to the 8th power, equals 64.