Write down four brackets with spaces on a piece of paper, ( )( ), like so.
factor the first term. In this case the possible factors for the first term is only 2 times 1. Write the factors for the first term in your brackets, (x )(2x ). Determine factors for the second term. In this case the possible factors for the second term are 1 times 30, 2 times 15, 3 times 10, and 5 times 6. Determine the factors and sign for the second term through guess and check. Since the second term in the equation is positive and the third term is negative, one sign must be positive and one must be negative. Through guess and check it can be determined that the correct factor is (x+10)(2x-3). If we check this we get 2x^2-3x+20x-30. Condensed we get 2x^2+17x-30
Use the quadratic formula. x = -4.265564 or -0.234436
(x - 3)(x + 5)
2x + 52 = 7 2x + 25 = 7 2x = 7 - 25 2x = -18 x = -18/2 x = -9
Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C
(2x + 1)(x + 2)
Add the x's squared together to get 2x^2+x. You cannot add anymore so the answer is 2x^2+x
Use the quadratic formula. x = -4.265564 or -0.234436
(x - 3)(x + 5)
17
2x + 52 = 7 2x + 25 = 7 2x = 7 - 25 2x = -18 x = -18/2 x = -9
-x2+2x
use the calculator
It is: 4x squared
2x2 + 2x = 2x(x+1)
x2 - 2x + 55 = 90x2 - 2x - 35 = 0(x+5)(x-7) = 0x = -5, 7
Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C
2x squared minus 5x minus 3 factored is (2x+1)(x-3).