Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C
Its often used to find the hypotenuse of a triangle. A squared + b squared would be the sides and the = c squared part that is most of the time what we want to solve for is the hypotenuse. However, you can also use pythagorean therem to solve any triangle side with the same triangle described above.
X (x - 25) So X = 0 Or X = +25
It depends on what you wanted to do - graph it, solve it, factorise it, etc.
y*y = 11y Divide both sides by y: y = 11
The 3s would cancel and it would become the integral of 1/x which is ln x.
do u mean solve 3 squared? if so it = 3x3x3 that's how u work it out so the answer would be 27. hope this helps :)
Its often used to find the hypotenuse of a triangle. A squared + b squared would be the sides and the = c squared part that is most of the time what we want to solve for is the hypotenuse. However, you can also use pythagorean therem to solve any triangle side with the same triangle described above.
It depends on what you wanted to do - graph it, solve it, factorise it, etc.
X (x - 25) So X = 0 Or X = +25
Your Problem: X - 4 = ?Current Problem: 3 [squared] - 4 = ?How: When a numbered is squared, it means you multiply it against itself. So, 3 squared equals 3x3.3x3 = 9So, you would then take 9 and minus it by 4, which would than equal 5.Answer:3 [squared] - 4 = 5or9 - 4 = 5
y*y = 11y Divide both sides by y: y = 11
you shouldn't be cheating u tard. it -24x +3 is ur answer
The symbol for squared is ², for example, 2 squared would be 2².
For it to be a definite integral, you would need to specify a range. We can however give you the indefinite integral. The easiest way to do this is to think of it not as a fraction, but as a negative exponent: 1/x2 = x-2 It then becomes quite easy to integrate, as we can say in general: ∫(axn) dx = ax(n + 1) / (n + 1) + C In this case then, we have: ∫(x-2) dx = -x-1 + C, or -1/x + C
The 3s would cancel and it would become the integral of 1/x which is ln x.
four squared would be sixteen
Particular integral is finding what the integral is for example the integral of 2x is x^2 + C. Finding the particular solution would be finding what C equals from the particular integral.