Mawmalade
Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C
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∙ 15y agoIts often used to find the hypotenuse of a triangle. A squared + b squared would be the sides and the = c squared part that is most of the time what we want to solve for is the hypotenuse. However, you can also use pythagorean therem to solve any triangle side with the same triangle described above.
X (x - 25) So X = 0 Or X = +25
It depends on what you wanted to do - graph it, solve it, factorise it, etc.
y*y = 11y Divide both sides by y: y = 11
The 3s would cancel and it would become the integral of 1/x which is ln x.
do u mean solve 3 squared? if so it = 3x3x3 that's how u work it out so the answer would be 27. hope this helps :)
Its often used to find the hypotenuse of a triangle. A squared + b squared would be the sides and the = c squared part that is most of the time what we want to solve for is the hypotenuse. However, you can also use pythagorean therem to solve any triangle side with the same triangle described above.
It depends on what you wanted to do - graph it, solve it, factorise it, etc.
X (x - 25) So X = 0 Or X = +25
Your Problem: X - 4 = ?Current Problem: 3 [squared] - 4 = ?How: When a numbered is squared, it means you multiply it against itself. So, 3 squared equals 3x3.3x3 = 9So, you would then take 9 and minus it by 4, which would than equal 5.Answer:3 [squared] - 4 = 5or9 - 4 = 5
y*y = 11y Divide both sides by y: y = 11
you shouldn't be cheating u tard. it -24x +3 is ur answer
For it to be a definite integral, you would need to specify a range. We can however give you the indefinite integral. The easiest way to do this is to think of it not as a fraction, but as a negative exponent: 1/x2 = x-2 It then becomes quite easy to integrate, as we can say in general: ∫(axn) dx = ax(n + 1) / (n + 1) + C In this case then, we have: ∫(x-2) dx = -x-1 + C, or -1/x + C
That factors to (x + 1)(x - 3) x = -1, 3
6x2 - x You don't have enough information to take this any further or solve it
The 3s would cancel and it would become the integral of 1/x which is ln x.
Please note that in general, if you have ONE equation with TWO or more variables, there is not a unique solution. You can assign an arbitrary value for "a", replace it, then calculate what would be the corresponding value of "b". Or, probably even better, you can solve for "b" in terms of "a". Then you can assign any value to "a", and calculate the corresponding value for "b". To actually solve for "b", first solve for b2 in the usual way, that is, manipulate the equation until b2 is on the left, everything else on the right. Then take the square root on each side.