3a + 11 = 7a - 13
subtract 3a from each side
3a - 3a + 11 = 7a - 3a - 13
11 = 4a - 13
add 13 to each side
11 + 13 = 4a - 13 + 13
24 = 4a
divide each sides integer by 4
24/4 = (4/4)a
6 = a
-------------check in original equation
3(6) + 11 = 7(6) - 13
18 + 11 = 42 - 13
29 = 29
----------------checks out
a = 4
r + 11 + 8r = 29
x = 5, y = -1
If: 7+t = 11 Then: t = 11-7 So: t = 4
You subtract 11 from both sides and r equals negative 7. See... r+11=3 -11 -11 r=7
a = 4
r + 11 + 8r = 29
9y subtract 11 equals 7
x = 5, y = -1
x=4 x=0
r + 11 = 19 r + 11 - 11 = 19 - 11 r = 8
If: 7+t = 11 Then: t = 11-7 So: t = 4
You subtract 11 from both sides and r equals negative 7. See... r+11=3 -11 -11 r=7
q = 78
6a + 5a = -11 Combining like terms: 11a = -11 Dividing by 11: a = -1
(0,7)
v is -15... -15*2 = -30... -30+11= -19.