If you are at a level that you need to ask this question then the likelihood is that you have made a mistake, since you are not likely to have learned about imaginary (or complex) numbers.
For the quadratic formula, first rewrite the equation as: 3x2 + 0x + 9 = 0
Then
a = 3, b = 0 and c = 9
So x = [0 ± √(02 - 4*3*9)]/(2*3)
= √-108/6 = √-3 = i√3 where i is the imaginary square root of -1.
If you set your equation to equal 7, then you can move 7 to the other side of the equation, and solve for x. This/these values will always result in 7. e.g. 3x2+11x+6=7 3x2+11x+6-7=7-7 3x2+11x-1=0 Factor using the quadratic formula and solve for x.
x=-.25.
The following is the answer:
Do you mean: 3x2+x-14 = 0 If so the solutions are: x = 2 and x = -7/3 using the quadratic equation formula
3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x
Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.
3x2+x-4 = 0 (3x+4)(x-1) = 0 Solutions: x = 1 and x = -4/3 By using the quadratic equation formula.
By using the quadratic equation formula which will work out as: x = 4- the square root of 32 and x = 4+the square root of 32
If you mean 3x2-7x+x = -4 then there are no solutions because the discriminant of the quadratic equation is less than zero.
Yes. (Assuming that -3x2 is the best representation of 3x2 that this browser will allow.)
Yes.
If you mean 3x2+4x-2 = 0 then it can be solved by means of the quadratic equation formulla
If you set your equation to equal 7, then you can move 7 to the other side of the equation, and solve for x. This/these values will always result in 7. e.g. 3x2+11x+6=7 3x2+11x+6-7=7-7 3x2+11x-1=0 Factor using the quadratic formula and solve for x.
The discriminant is -32.
x=-.25.
The following is the answer:
Do you mean: 3x2+x-14 = 0 If so the solutions are: x = 2 and x = -7/3 using the quadratic equation formula