If you are at a level that you need to ask this question then the likelihood is that you have made a mistake, since you are not likely to have learned about imaginary (or complex) numbers.
For the quadratic formula, first rewrite the equation as: 3x2 + 0x + 9 = 0
Then
a = 3, b = 0 and c = 9
So x = [0 ± √(02 - 4*3*9)]/(2*3)
= √-108/6 = √-3 = i√3 where i is the imaginary square root of -1.
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If you set your equation to equal 7, then you can move 7 to the other side of the equation, and solve for x. This/these values will always result in 7. e.g. 3x2+11x+6=7 3x2+11x+6-7=7-7 3x2+11x-1=0 Factor using the quadratic formula and solve for x.
The following is the answer:
Do you mean: 3x2+x-14 = 0 If so the solutions are: x = 2 and x = -7/3 using the quadratic equation formula
3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x
3x2 + 2x - 8 = 0 is a quadratic equation.