By using the quadratic equation formula which will work out as:
x = 4- the square root of 32 and x = 4+the square root of 32
3x^(2) + 24x = 0 Divide by '3' x^(2) + 8 = 0 x^(2) = - 8 x = sqrt(-8) Yjis is NOT resolved as you cannot take the squate root of a negative number, without going into IMAGINARY numbers. x = sqrt( -1 X 8) x = sqrt(-1) X sqrt(8) x= sqrt(-1) X 2sqrt(2) Sqrt(-1) is shown as 'i' ( small/lower case 'i' , algebraically). Hence x = 2sqrt(2) i
3x2-24x-48 is not factorable.
No real roots.
3(2) + 24x + 48 = 0 6 + 24x + 48 = 0 24x + 54 = 0 24x + 54 - 54 = 0 - 54 24x = -54 24x/24 = -54/24 x = -9/4 x = -2 1/4
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
GCF = 12x.24x = 2(12x)36x3 = 3x2(12x)
If you mean 3x2-7x+x = -4 then there are no solutions because the discriminant of the quadratic equation is less than zero.
3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x
3x(x - 8)
6x(3x2 - x + 4)
Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.
y = 3x^(2) + 24x - 1 Differentiate and equate to '0' dy/dx = 6x - 24 = 0 6x - 24 = 0 6x = 24 x = 4 is the line of symmetry.