Someone's homework? This is a pair of simultaneous equations: 1) 3x - 4y = 10 2) y = x - 3 Substituting for y in equation 1: 3x - 4(x-3) = 10 3x - 4x + 12 = 10 -x + 2 = 0 -x = -2 x = 2 substitute into equation 2: y = 2 - 3 y = -1
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3x - 4y = 10-3x - 4y = 8 -> add line 1 to line 2 3x - 4y = 100x - 8y = 18 -> -8y = 18 -> y = -18/8 = -9/4 -> 3x - 4*(-9/4) = 10 -> 3x + 9 = 10 -> 3x = 1 -> x = 1/3
(2, -1)
2x+3xy-4y=10to solve for yyour objective will be to get y by itself on one side of the equal signyou first subtract 2x to get the terms with y variables on one side3xy-4y=10-2xthen undistribute the y from the two terms to get one yy(3x-4)=10-2xnow divide 3x-4y=(10-2x)/(3x-4)theres your answer
x = 4 and y = 0
i dont know what you are trying to solve for, but if you are solving for x and y. u have to...... 3x-4y=4 x= 4/3..... 1.33 y=4/-4...... -1