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Earn +20 ptsQ: How do you solve 3x over 2 equals 1 over 4?
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Solve 5x2 minus 3x minus 1 equals 0?
5*2-3x-1 = 0 10-3x-1 = 0 -3x = 1-10 -3x = -9 x = 3
Could you Solve the following equation 3x-1 equals 7?
3x-1 = 7 3x = 8X= 8/3 = 2+2/3
How do you solve 2xplus 1 over 3x equals xminus 1 over 5x?
one way to solve an equation in this format, "a/b = c/d", is to multiply both sides by "b"and by "d". You're effectively "cross multiplying" the fractions: (2x + 1) / 3x = (x - 1) / 5x ∴(2x + 1)(5x) = (x - 1)(3x) ∴10x2 + 5x = 3x2 - 3x You can then factor an "x" out of both sides ∴10x + 5 = 3x - 3 And rearrange to solve: ∴10x - 3x = -3 -5 ∴7x = -8 ∴x = -8/7
How can you solve 3x-4y16 letting y equals -1?
That's not an equation you can solve, since it doesn't have an equal si Assuming you mean: 3x - 4y = 16 For a start, you should replace y with -1. Then solve the resulting equation: 3x - 4(-1) = 16 for x.
3x-y equals -1?
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