x = 7
7-4/3 x 7 = 1/7
3/21 = 1/7
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
You cannot solve one linear equation in two unknown variables.
"2 over 3x equals 4" is an equation in a single variable, x.2/(3x) = 4 => 3x/2 = 1/4 => 3x = 2/4 = 1/2 => x = 1/6.
The easiest way to solve this system of equations is to solve for a variable in one of the equations. In the second equation, y = 3x. This can be substituted into the first equation: y = -4x - 7; 3x = = -4x - 7; 7x = -7; x = -1. Since we have determined that x equals -1, we can then substitute -1 into either equation to find our corresponding y-value. Thus: y = 3x; y = 3(-1) y = -3. Thus, the solution to this system of equations is (-1, -3).
-3x = 3 + y 3 + y - 5y = -21 -4y = -24 y = 6 x = -3
x equals 4 over 35
2y-3x=4
18=3(3x-6)
12/3 = 4
x = 6
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
Quadratic equation formula
First, subtract 3x from each side of the equation. Then, divide each side of the equation by 7 .
X = 12
The answer is dividing. 3x=24 3x/3=24/3 x = 8
Add 5 to both sides of the equation to get rid of the - 5. -3x - 5 + 5 = -20 + 5 Solve and simplify. -3x = -15 Divide both sides of the equation by -3. x = 5
3x-5y=15 The equation-5y=15-3x Subtract 3x from both sidesy=-3+.6x Divide both sides by -5