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Q: How do you factor 5x squared minus 27x plus 10?

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9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)

I also need to know the answer to this problem. Can anyone answer it?

27x-3=105 27x=105+3 27x=108 x=108/27 x=4ans

Add 7x to each side: 136 = 27x + 20 Subtract 20 from each side: 116 = 27x Divide each side by 27: x = 116/27 = 4 & 8/27.

It is: 27x

Related questions

9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)

3(3x + 2)(3x - 2)

9x(x2+3x-10)

the answer is (3x-2)(9x squared+6x+4)

3x2 + 27x +60

9xy(3xy - 4)

(8x + 9)(3x^2 - 1)

I also need to know the answer to this problem. Can anyone answer it?

You try to find two factors of -58 whose sum is -27 .You find that -29 and +2 will do it, so . . .x2 - 27x - 58 = (x - 29) (x + 2)

20x2 - 27x -8 20 * -8 is -160, and -32 and 5 add to -27 20x2 - 32x + 5x - 8 4x(5x-8) + 1(5x-8) (4x + 1)(5x-8)

Divide the entire equation by 9. (9x2 + 27x + 18)/9 would then be 9(x2 + 3x +2) The factors of this equation would be 9(x + 1)(x + 2)

16x2 + 27x - 28 doesn't factor. Applying the quadratic formula, we find two real solutions:(-27 plus or minus the square root of 2521) divided by 32x = 0.725298776329149x = -2.412798776329149

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