3x2 + 2x = 16
∴ 3x2 + 2x - 16 = 0
∴ 3x2 - 6x + 8x - 16 = 0
∴ 3x(x - 2) + 8(x - 2) = 0
∴ (3x + 8)(x - 2) = 0
∴ x ∈ {-8/3, 2}
x^(2) - 10x + 16 = 0 Factors of '16', which are, 1,2,4,8,16. Select two numbers from this list that add/subtract to '10' . They are '2' and '8'. Setting up brackets ( x 2)(x 8) Since '16' is positive(+), then both signs must be the same. Since '10x' is negative (-) , then both signs are negative. Hence (x - 2)(x - 8 ) = 0 When x - 2 = 0 x = 2 & when x - 8 = 0 x = 8 So the two answers are ,2, & ,8, .
16
(b-4) squared
2 squared plus 2 squared equals 16 because 2 squared is 4 times 4 equals 16. Math: 4x4=16 so your answer is 16 :)!
By factoring. q2 + 16q = 0 q (q + 16) = 0 Now, either q = 0, or q + 16 = 0. Solve those two equations to get the solution.
20
x = -8
(x + 4)(x +4) or (x + 4)squared
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
h=16
{-1,7}
x^(2)-16=0 Take the -16 over to the other side of the equal sign, the -16 will turn +16. x^(2)=16 Then take the squared root of both sides. x=4