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Anonymous
3x2 + 2x = 16
∴ 3x2 + 2x - 16 = 0
∴ 3x2 - 6x + 8x - 16 = 0
∴ 3x(x - 2) + 8(x - 2) = 0
∴ (3x + 8)(x - 2) = 0
∴ x ∈ {-8/3, 2}
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Solve using the quadratic formula
16
(b-4) squared
h=16
y=16 x= -4