3x2 + 2x = 16
∴ 3x2 + 2x - 16 = 0
∴ 3x2 - 6x + 8x - 16 = 0
∴ 3x(x - 2) + 8(x - 2) = 0
∴ (3x + 8)(x - 2) = 0
∴ x ∈ {-8/3, 2}
Solve using the quadratic formula
16
(b-4) squared
32 + x = 259 + x = 25x = 25 - 9x = 16
2 squared plus 2 squared equals 16 because 2 squared is 4 times 4 equals 16. Math: 4x4=16 so your answer is 16 :)!
By factoring. q2 + 16q = 0 q (q + 16) = 0 Now, either q = 0, or q + 16 = 0. Solve those two equations to get the solution.
x = -8
20
(x + 4)(x +4) or (x + 4)squared
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
h=16
y=16 x= -4