How do you solve 3x squared plus 2x equals 16?

Answer 1

3x2 + 2x = 16

∴ 3x2 + 2x - 16 = 0

∴ 3x2 - 6x + 8x - 16 = 0

∴ 3x(x - 2) + 8(x - 2) = 0

∴ (3x + 8)(x - 2) = 0

∴ x ∈ {-8/3, 2}