3x2 + 9x + 2 is an expression; it is NOT an equation. You cannot solve an expression.
However, if you did have an equation: 3x2 + 9x + 2 = 0
Then dividing through by 3 gives: x2 + 3x + 2/3 = 0
or x2 + 3x = - 2/3
Completing the square on the left (add 9/4 to both sides) : x2 + 3x + 9/4 = 9/4 - 2/3 = 19/12
(x + 3/2)2 = 19/12
(x + 3/2) = +/- sqrt(19/12)
So x = -3/2 +/- sqrt(19/12)
It cannot be solved because the discriminant of the quadratic equation is less than zero
_t(5t squared t+)
Please do not remove this question from Inappropriate or split any alts from it. Thanks!
hello
(b-4) squared
It cannot be solved because the discriminant of the quadratic equation is less than zero
No because the discriminant of the given quadratic expression is less than zero.
x=9 squared
x² + 3x - 1 = [ x² + 3x + (3/2)²] - 1 - (3/2)² = (x + 3/2)² - 1 - (9/4) = (x + 3/2)² - (13/4) if you are still confused, i want you to follow the related link that explains the concept of completing the square clearly.
_t(5t squared t+)
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
Please do not remove this question from Inappropriate or split any alts from it. Thanks!
hello
(b-4) squared
This question cannot be answered. You will have to give me the number to the square root. * * * * * a = ±sqrt(c^2 - b^2)
This quadratic equation has no solutions because the discriminant is less than zero.
X + y