2 + 3 / 5y = 25 / 5y = 2(x both sides by 5y)5 = 10y(divide both sides by 10)0.5 = yy = 0.5Check...5/(5 x 0.5) = 25/2.5 = 2
7
Divide 3.25 by 5 and get .65
2x-5y=5 In order to solve this linearly(in points), you must plug in numbers into x or y, then solve the equation for the other variable. For example: if you plug 0 into x, or into y. You will need to do this with at least two points, three two be safe. 2(0)-5y=5 2x-5(0)=5 0-5y=5 2x=5 0-5y-0=5-0 2x/2=5/2 -5y=5 x=5/2 -5y/-5=5/-5 (5/2,0) y=-1 You then create a graph and plot the points. Next, draw a (0,-1) connecting the two points, and...voila! you have put 2x-5y=5 into points on a line.
5y - 2 = 28 - y 5y + y = 28 + 2 6y = 30 y = 30/6 y = 5
2x+5y=20 Solve for y -2x -2x 5y=20-2x 5 5 5 y=4-2x 5
5y-4 = 7 5y = 7+4 = 11 y = 11 / 5 = 2.2
2 + 3 / 5y = 25 / 5y = 2(x both sides by 5y)5 = 10y(divide both sides by 10)0.5 = yy = 0.5Check...5/(5 x 0.5) = 25/2.5 = 2
7
Divide 3.25 by 5 and get .65
2x-5y=5 In order to solve this linearly(in points), you must plug in numbers into x or y, then solve the equation for the other variable. For example: if you plug 0 into x, or into y. You will need to do this with at least two points, three two be safe. 2(0)-5y=5 2x-5(0)=5 0-5y=5 2x=5 0-5y-0=5-0 2x/2=5/2 -5y=5 x=5/2 -5y/-5=5/-5 (5/2,0) y=-1 You then create a graph and plot the points. Next, draw a (0,-1) connecting the two points, and...voila! you have put 2x-5y=5 into points on a line.
-x + 5y = 10 5y= 11 y = 11/5
5y - 2 = 28 - y 5y + y = 28 + 2 6y = 30 y = 30/6 y = 5
6X + 5Y = 8 subtract 6X from both sides 5Y = -6X + 8 divide both sides by 5 Y = -6/5X+ 8/5 now you have a line of slope -6/5 that intersects the Y axis at 8/5. (Solve for X to get X intercept)
(20 - x)/5
7y + 4 = 5y - 6Subtract 4 from each side:7y = 5y - 10Subtract 5y from each side:2y = -10Divide each side by 2:y = -5
Solved for y: y=(3x-13)/5 Solved for x: x=(5y+13)/3