If you mean: 4x+5y=-20 then the y intercept is (0, -4) and x intercept is (-5, 0)
2 and 5 are coefficients of x and y respectively.
Answer: y = -2/5x-14/5 which also can be written as 5y = -2x-14 or in the general form of the equation of a straight line as 2x+5y+14 = 0
x intercept = (5, 0) y intercept = (0, -2)
2x + 3y - x + 5y combine the like terms 2x - x + 3y +5y simple arithmetic x + 8y
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
what is the solution of x-5y=10 and 2x-10y=20
0 = -2x + 5y - 15 -5y = -2x - 15 y = 2x/5 + 3
2X - 5Y = 10 ???? If so. 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
Known equation: 5x -2y=3 => y=5/2x -1.5 Slope of equation: 5/2 Perpendicular slope: -2/5 Perpendicular equation: y--4=-2/5(x-3) => 5y--20=-2x+6 => 5y=-2x-14 Therefore the perpendicular in its general form is: 2x+5y+14 = 0
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
2x-5y = -10 -5y = -2x-10 y = 2/5x+2 which is in slope intercept form
Without an equality sign the terms given can't be considered to be an equation. But straight lines are parallel to each other if they have the same slope and different y intercepts.
2
Another straight line equation is needed such that both simultaneous equations will intersect at one point.
If you mean: 2x+5y = 10 then the x intercept is5 and the y intercept is 2