You could divide each side by 't' to get 9t2=16 , then divide each side by 9 to get t2=16/9 ,
then take the square root of each side to get t=(plus or minus) 9 .
That would give you two of the three solutions that you know a 3rd degree equation must have.
You could look back at your original equation, scratch your chin for a moment, and realize that
t=0 is also a solution.
16t plus 7 equals 19t plus 10. 16t+7=19t+10. Subtract 16t and 10 from both sides. -3=3t -1=t
9t=702 t=702/9 t=78
100t -16t2 = 0 t4(25-4t) = 0 t = 0 or t = 25/4
9t = 4t + 120 9t-4t = 4t - 4t + 120 5t = 120 5t/5 = 120/5 t = 24 24 is your answer
16t(t + 4) is the factorization Usually it's set = to 0 16t (t+4) =0 So, either 16t = 0 or t + 4 = 0 t = 0 or t = -4
9t + 15t= 216 24t=216 t=216/24 t=9
Solve this problem -x squared -40x- 80 =0
S=vt-16t2 solve for v is what I will assume you mean. first pull out the t S=t(v-16t) then devide by t S/t=v-16t Then add 16t to both sides S/t + 16t = v This can also be written as (S+16t2)/t = v
16t plus 7 equals 19t plus 10. 16t+7=19t+10. Subtract 16t and 10 from both sides. -3=3t -1=t
9t=702 t=702/9 t=78
0.37 cup
Yes.
100t -16t2 = 0 t4(25-4t) = 0 t = 0 or t = 25/4
1.5
9t = 4t + 120 9t-4t = 4t - 4t + 120 5t = 120 5t/5 = 120/5 t = 24 24 is your answer
-12t+4
16t(t + 4) is the factorization Usually it's set = to 0 16t (t+4) =0 So, either 16t = 0 or t + 4 = 0 t = 0 or t = -4