x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
Assuming that the question is find x in x5=1610; the answer is 4.378901
Integral of x3/2dx using power rule = (5/2)x5/2 2.5 times the square root of x to the fith.
x5 is an expression, not an equation nor an inequality. An expression cannot be solved.
1,565 = x5 1,5651/5 = (x5)1/5 1,5651/5 = x5/5 1,5651/5 = x 4.3541 = x
x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
This can either be written as x5.5, or x5 times square root of x. √x11 = √x10x = x5√x
Assuming that the question is find x in x5=1610; the answer is 4.378901
x3/x1/2 = x5/2.
x5 = 33 1/3, solve for x. x is the fifth root of 33 1/3. If your scientific calculator doesn't have a specific key for nth. root, raise the number to the power 0.2 (that is, 1/5).
Integral of x3/2dx using power rule = (5/2)x5/2 2.5 times the square root of x to the fith.
a(x5) + b(x5) + c(x5) + d(x5) + e(x5) = abcde(a+b+c+d+e) x5 = abcdeThis equation has at least 5 variables. To solve for all of them requires at least 4 more equations.
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
x5 is an expression, not an equation nor an inequality. An expression cannot be solved.
The same way as you find the square root with an even-numbered exponent. For example, the square root of x10 is x5. That is, divide the exponent by 2. Similarly, the square root of x7 is x3.5. Once again, you simply calculate one-half of the exponent. If you prefer to express this with integer exponents and square roots, in this example you can write x3.5 as x3x0.5. The second part, x0.5, is equivalent to the square root of "x".
∛(x4) √(x5) = x4/3x5/2 = x8/6x15/6 = x23/6
1,565 = x5 1,5651/5 = (x5)1/5 1,5651/5 = x5/5 1,5651/5 = x 4.3541 = x