Requires another equation. One thing is for sure though. Whatever x is it must be greater or equal than 5.
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x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
Assuming that the question is find x in x5=1610; the answer is 4.378901
Integral of x3/2dx using power rule = (5/2)x5/2 2.5 times the square root of x to the fith.
x5 is an expression, not an equation nor an inequality. An expression cannot be solved.
1,565 = x5 1,5651/5 = (x5)1/5 1,5651/5 = x5/5 1,5651/5 = x 4.3541 = x