Try this one.
All the sums are ' 1 '.
[8/15] [ 1/15] [ 2/5 ]
[ 1/5 ] [ 1/3 ] [ 7/15 ]
[4/15] [ 3/5 ] [ 2/15 ].
To solve a magic square with a magic constant of 111 using the numbers 7, 13, 31, 37, 43, 61, 67, 73, and 61, you need to arrange these numbers in a 3x3 grid such that each row, column, and diagonal sums to 111. Start by calculating the center of the square, which should be the average of the numbers used (in this case, it's 43). Then, systematically place the remaining numbers around the center while ensuring that the sums of all rows, columns, and diagonals equal 111. Adjust placements as needed until the conditions of the magic square are satisfied.
A 3x3 magic square has the property that the sum of the numbers in each row, column, and diagonal is the same. For a 3x3 magic square using the numbers 1 to 9, the magic constant is 15, not 18. If you're referring to a different set of numbers or a modified version of a magic square, please specify the numbers used to achieve a magic constant of 18.
In an 8x8 magic square, the sum of each row, column, and diagonal is the same, known as the magic constant. For an n x n magic square, the magic constant can be calculated using the formula ( M = \frac{n(n^2 + 1)}{2} ). For an 8x8 magic square, this gives ( M = \frac{8(64 + 1)}{2} = 260 ). Therefore, the sum in the 1st row of an 8x8 magic square is 260.
Excluding reflections and rotations, there is only one 3x3 magic square using 1-9.
By using the quadratic equation formula
write a vb program to find the magic square
A 3x3 magic square has the property that the sum of the numbers in each row, column, and diagonal is the same. For a 3x3 magic square using the numbers 1 to 9, the magic constant is 15, not 18. If you're referring to a different set of numbers or a modified version of a magic square, please specify the numbers used to achieve a magic constant of 18.
The answer will depend on the exact nature of the equation.
In an 8x8 magic square, the sum of each row, column, and diagonal is the same, known as the magic constant. For an n x n magic square, the magic constant can be calculated using the formula ( M = \frac{n(n^2 + 1)}{2} ). For an 8x8 magic square, this gives ( M = \frac{8(64 + 1)}{2} = 260 ). Therefore, the sum in the 1st row of an 8x8 magic square is 260.
123 123 123
Excluding reflections and rotations, there is only one 3x3 magic square using 1-9.
By using the quadratic equation formula
its impossible because in a 4 by 4 magic square u need 16 numbers u cant do it with just 0-9
Yes. One solution is: -4 16 -12 -8 0 8 12 -16 4
If you are using square roots, the simplest way of solving: ax2 + bx + c = 0 is x = [-b ± sqrt(b2-4ac)]/(2a)
Excluding rotations and reflections, there is only one 3x3 magic square.
its just using fractions but not more than once to make other fractions