Solve it for 'y' .
Unanswerable in current form. Perhaps an"equation chart" is a table of values?
You need to find the slope in the equation.
Points: (x1, y1) and (x2, y2) Slope: y1-y2/x1-x2
If you solve such an equation for "y", you get an equation in the slope-intercept form.
The slope of a time-distance chart would be a constant. The slope of a time-velocity chart would be 0.
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
To solve this, use the slope formula. the slope formula is m = (y2 - y1) / (x2 - x1) Therefore, m = ( -3 - 5)/ (1-2) If you solve this, you will get 8. So the slope of the line is 8.
Solve it for 'y' .
Unanswerable in current form. Perhaps an"equation chart" is a table of values?
You take the change in Y or dy and divide it by the change in X or dx. Slope equals dy/dx.
8
You need to find the slope in the equation.
Points: (x1, y1) and (x2, y2) Slope: y1-y2/x1-x2
If you solve such an equation for "y", you get an equation in the slope-intercept form.
Plot its straight line equation on the Cartesian plane
Y = - 3X + 2 - 3 is the slope here ============== Whenever, you want to find the slope of a line, you first solve for the y = mx + b form of the function and then "m" is your slope.