Solve it for 'y' .
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
the square
Just write the equation as: (x - 11)(x - 3) = 0 and convert it to any form you like.
whats the equation to convert meters to inches?
To convert a quadratic equation from vertex form, (y = a(x - h)^2 + k), to standard form, (y = ax^2 + bx + c), you need to expand the equation. Start by squaring the binomial: ( (x - h)^2 = x^2 - 2hx + h^2 ). Then, multiply by (a) and add (k) to obtain (y = ax^2 - 2ahx + (ah^2 + k)), where (b = -2ah) and (c = ah^2 + k). This results in the standard form of the quadratic equation.
y = 2x + 1.
Solve the equation for ' y '.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
square
To convert a quadratic equation from standard form (ax^2 + bx + c) to factored form, you first need to find the roots of the equation by using the quadratic formula or factoring techniques. Once you have the roots, you can rewrite the equation as a product of linear factors, such as (x - r1)(x - r2), where r1 and r2 are the roots of the equation. This process allows you to express the quadratic equation in factored form, which can be useful for solving and graphing the equation.
You also need an equation for y in order to convert to rectangular form.
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
the square
You can take the logarithm on both sides of an equation. The real trick is to figure out when this will help you to solve the equation, and when not.
Just write the equation as: (x - 11)(x - 3) = 0 and convert it to any form you like.
whats the equation to convert meters to inches?
It's possible