Although the answer below would suggest otherwise, it can be proved that a single linear equation in two variable cannot be solved. The whole point of it is that it is a linear equation which represents a line. The coordinates of ANY (repeat ANY) point on the line will satisfy the equation - not just 1, not 3, nor 5 nor 6000 but infinitely many points. Each and every point on the line is a solution.
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Easy, as long as you follow these steps.
Lets say you are given an equation such as
25 = 2x+2y
You have two variables! Oh no! Well, now take this one step at a time, because it's a multiple step equation.
25 = 2x+2y (divide both sides by 2)
25/2 = 12.5
2x/2 = x
2y/2 = y
Now you have 12.5 = x + y
You still have two variables, but now you can work with them a bit better.
Considering this is an equation that would normally just be simplified, you must substitute any number greater than zero, but less than or equal to 12.5, for either x or y.
x = 11.5
Subtract the substitution of x (11.5) from the answer (q) and you will get
1 = y
Now you have both the value of your x and the value of the y.
x = 11.5
y = 1
12.5 = 11.5 + 1
However, you could substitute a number greater than 12.5 such is demonstrated below.
12.5 = x + y
x = 13.5
Now subtract x from your answer (q) and you will get
y = -1
Substitute the values again and you will get
12.5 = 13.5 - 1
Both are true, but you need to go back to the original equation now. You need to multiply both sides by two to get your final answer.
25 = 2x+2y
25 = 2(11.5)+2(1) is your final answer
OR
25 = 2(13.5)+2(-1) could also be your final answer, depending on which you chose.
2+2
Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.
The equation 4y = 2x + 2 cannot just be solved. If you are trying to solve a system, you need as many equations as you have variables (x and y in this case). Since you have two variables, you need two equations.For example, if you had:4y = 2x + 2 AND 2y = 4x + 4, then it would be possible to solve like so....first solve for one of the variables in one of the equations. Let's go for y in the second equation.2y = 4x + 4 ----> 2y/2 = 4x/2 + 4/2 ----> y = 2x + 2.now use this value of y and place it into the first equation and then you can solve for x.4(2x + 2) = 2x + 2 ----> 8x + 8 = 2x + 2 ----> 6x = -6 ----> x = -1now you can replace the -1 into either equation and solve for y4y = 2(-1) + 2 ----> 4y = -2 + 2 ----> 4y = 0 ----> y = 0So, if there is another equation for you to solve with, you can easily use this method to solve for both variables.
a+b=16 is a linear equation in two variables. The variables are a and b. To solve a linear equation in 2 variables we need more information. We need either another equation, or a value to put in for a or b.Since we have neither, there is no more we can do.
It is not possible to solve one linear equation in two unknown variables. Another, independent equation is required.
2+2
Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.
1
The equation 4y = 2x + 2 cannot just be solved. If you are trying to solve a system, you need as many equations as you have variables (x and y in this case). Since you have two variables, you need two equations.For example, if you had:4y = 2x + 2 AND 2y = 4x + 4, then it would be possible to solve like so....first solve for one of the variables in one of the equations. Let's go for y in the second equation.2y = 4x + 4 ----> 2y/2 = 4x/2 + 4/2 ----> y = 2x + 2.now use this value of y and place it into the first equation and then you can solve for x.4(2x + 2) = 2x + 2 ----> 8x + 8 = 2x + 2 ----> 6x = -6 ----> x = -1now you can replace the -1 into either equation and solve for y4y = 2(-1) + 2 ----> 4y = -2 + 2 ----> 4y = 0 ----> y = 0So, if there is another equation for you to solve with, you can easily use this method to solve for both variables.
a+b=16 is a linear equation in two variables. The variables are a and b. To solve a linear equation in 2 variables we need more information. We need either another equation, or a value to put in for a or b.Since we have neither, there is no more we can do.
It is not possible to solve one linear equation in two unknown variables. Another, independent equation is required.
There can be linear equations with 1, 2, ... variables. Each of these is different since an equation with n variables belongs to n-dimensional space.
An equation with only one variable has only one letter used in it, and that letter is usually an "x" An equation having two variables will have two different letters representing them, usually the letters "x" and "y" The first type could be the equation 5x^3 - 3x^2 + 6x - 50 = 0 The second type could be (x +y)^2 - 7x^3 + 12x = 58.8 1 equations with only 1 variable are usually much easier to solve than an equation with 2 variables, and you cannot solve the latter unless you have two separate equations containing the two variables.
You cannot solve 1 linear equation in 2 unknown variables. You need at least two independent equations.
Mathematical substitution is the process of using one equation to solve for multiple variables. For example: Equation 1: x + y = 4 Equation 2: 2x + y = 16 Using equation 1, solve for y: y = 4 - x <-- Plug this into equation 2. This is substitution because you are replacing y in equation 2 with what y is equal to in equation 1. 2x + y = 16 ----> 2x + (4 - x) = 16 Now you can solve for x: x + 4 = 16; x = 12 You can then substitute the value of x back into the equation that is solved for y: y = 4 - 12; y = -8 Check both equations: Equation 1: -8 + 12 = 4; 4 = 4 (Correct) Equation 2: 2(12) + (-8) = 16; 24 - 8 = 16; 16 = 16 (Correct) We have successfully used substitution to solve for two different variables, x and y.
A single equation with two variables can be solved for one of the variables, in terms of the other. For example, a rectangle's area is A = wh (width x height). Now let's assume you know the area: 20 = wh. You can solve for any of these variables in terms of the other, for example, w = 20/h. That is, once you assign a value to "h", you can calculate "w". But you don't know the specific values for "w" and "h", because the equation has an infinite number of solutions.If you want to know specific values for the variables, in general, you need two different equations with 2 variables - or 3 equations with 3 variables, etc.
To solve the equation you need to know at least a value for x or y. For example if x = 2 then the solution will show that y = 1.