2x+8=10... Subtract 8 on both sides, then devide by 2... 2x=2... x=1
2x - 1 = 3x + 4 Subtract 2x from both sides: - 1 = x + 4 Subtract 4 from both sides: -5 = x
2x+32 = 1 2x = 1-32 2x = -31 x = -15.5
2x+1 = 9 2x = 9-1 2x = 8 x = 4
get it to y= -2y = 1 - 2x y = x - 0.5
x + 8y = 3 therefore 2x + 16y = 6 (a) 2x + 3y = -7 (b) Subtract (b) from (a): 13y = 13 so y = 1 and x = -5
meant to be e^x = 2e^1-2x
2x + 1 = 9 2x = 9 - 1 2x = 8 2x/2 = 8/2 x=4
To solve this equation, we will first subtract 2x from each side:8x=2x+6 (8x minus 2x=6x)6x=6Now, to isolate x, we must divide out the 6:6x=6 (6x divided by 6= x)x=1If 8x=2x+6, x=1
If: 2x-1 = 2Then: 2x = 2+1And: 2x = 3So: x = 3/2 = 1.5 or 1 and a 1/2
3
X = 0 (zero) Y = -1 (neg 1)