The standard form of a quadratic equation in one variable is ax^2 + bx + c = 0.
There is a new solving method, called Diagonal Sum Method (Amazon e-book 2010) that can directly give the 2 real roots without factoring. It uses a Rule of Signs for Real Roots and a Rule for the Diagonal Sum. To know how to proceed with this new method, please read the article:"Solving quadratic equations by the Diagonal Sum method" on this Wiki Answers website.
Depending on the values of the constants a and c, solving quadratic equations may be simple or complicated.
A. When a= 1. Solving by the new method is simple and doesn't need factoring.
B. When a and c are prime/small numbers, the new method directly selects the probable root pairs from the (c/a) setup. Then it applies a simple formula to calculate all diagonal sums of these probable root pairs to find the real root pair.
C. Complicated cases: When a and c are large numbers and contains themselves many factors.
In these cases, students are advised to write down the (c/a) setup. The numerator of the setup contains all factors-sets of c. The denominator contains all factors-sets of a. Next, the new Diagonal Sum Method transforms a multiple step solving process into a simplified one by doing a few elimination operations.
Example 1. Solve: 45x^2 - 74x - 55 = 0.
Solution. Rule of sign indicates two roots have opposite signs. All-options-line:
Numerator. Factors-sets of c = -55: (-1, 55) (-5, 11)
Denominator. Factors-sets of a = 45: (1, 45)(3, 15)(5, 9)
Now, you may use mental math to calculate all diagonal sums and find the one that fits. However, the best way is to transform the c/a setup into its simplest form by doing a few eliminations.
First, eliminate the pairs (-1, 55)/(1, 45)(3, 15) because they give large diagonal sums, compared to b = 74. The simple remainder c/a: (-5, 11)/(5, 9) leads to the unique root pair: (-5/9 & 11/5). Its diagonal sum is -25 + 99 = 74 = -b. The two real roots are: -5/9 and 11/5.
Example 2. Solve: 12x^2 - 272x + 45 = 0.
Solution. Both roots are positive. Write down the (c/a) setup.
Numerator: (1, 45) (3, 15) (5, 9)
Denominator: (1, 12) (2, 6) (3, 4)
First, eliminate the pairs (1, 12) and (3, 4) because they give odd-number diagonal sums, while b is and even number. Next, look for a large diagonal sum (-272). The fitted (c/a) should be (1, 45)/(2, 6) that give 2 probable roots-sets: (1/2 & 45/6) and (1/6 & 45/2). The diagonal sum of the second set is 270 + 2 = 272 = -b. The 2 real roots are: 1/6 and 45/2.
Example 3. Solve: 45x^2 - 172x + 36 = 0.
Solution. Both roots are positive. Write down the (c/a) setup.
Numerator: (1, 36) (2, 18) (3, 12) (6, 6)
Denominator: (1, 45) (3, 15) (5, 9)
First, eliminate the pairs (1, 36) (3, 12) since they give odd-number diagonal sums (while b is even). Then, eliminate the pairs (6, 6)/(3, 15) because they give diagonal-sums that are multiples of 3. This would make the given equation be simplified by 3. The remainder probable root pairs are: (2, 18)/ (1, 45) and (2, 18)/(5, 9). The second c/a gives 2 probable real roots-sets (2/5 & 18/9) and (2/9 & 18/5). The second set has as diagonal sum: 172 = -b. The 2 real roots are 2/9 and 18/5.
Example 4. Solve 24x^2 + 59x + 36 = 0.
Solution. Both roots are negative. Write the (c/a) setup.
Numerator: (-1, -36) (-2, -18) (-3, -12) (-4, -9) (-6, -6)
Denominator: (1, 24) (2, 12) (3, 8) (4, 6)
First, eliminate the pairs (-2, -18)(-6, -6)/(2, 12) (4, 6) because they give even-number diagonal sums (while b is odd). Then, eliminate the pairs (-1, -36) (-2, -18)/(1, 24) since they give too large diagonal sums (b = -59). The remainder c/a is (-4, -9)/(3, 8) that gives the 2 real roots: -4/3 and -9/8.
Comments. We see that the new Diagonal sum method can transform a multiple step solving process into a simplified one by doing a few elimination operations. With practices and experiences, students will feel the above operations routine and they can surely find the real root pair that fits. It may be simpler if you solve these complicated equations by the quadratic formula with a calculator. However, performing the above operations helps fulfill the goal of learning math, that is to improve logical thinking and deductive reasoning. It would be a boring hard work if you have to solve these complicated equations by the quadratic formula without a calculator, during some tests/exams for examples.
The Quadratic formula in mathematics is used to solve quadratic equations in algebra. The simplest way to solve these equations is to set each of the factors to zero and then solve each factor separately.
josh hutcherson
Factor it! Set each equal to zero! Solve
There are several ways to solve such equations: (1) Write the equation in the form polynomial = 0, and solve the left part (where I wrote "polynomial"). (2) Completing the square. (3) Use the quadratic formula. Method (3) is by far the most flexible, but in special cases methods (1) and (2) are faster to solve.
If the discriminant - the part under the radical sign in the quadratic formula - is negative, then the result is complex, it is as simple as that. You can't convert a complex number to a real number. If a particular problem requires only real-number solutions, then - if the formula gives complex numbers - you can state that there is no solution.
The Quadratic formula in mathematics is used to solve quadratic equations in algebra. The simplest way to solve these equations is to set each of the factors to zero and then solve each factor separately.
josh hutcherson
1+1=2
Graphically might be the simplest answer.
The quadratic formula is used to solve the quadratic equation. Many equations in which the variable is squared can be written as a quadratic equation, and then solved with the quadratic formula.
It is used to solve quadratic equations that cannot be factored. Usually you would factor a quadratic equation, identify the critical values and solve, but when you cannot factor you utilize the quadratic equation.
Because it's part of the quadratic equation formula in finding the roots of a quadratic equation.
Wolfram Alpha can solve not just quadratic equations, but all sorts of equations. Note that in this particular website, you can see the solution for free, but you need a paid subscription to show the steps. I am sure there are other websites that can help you as well; you may want to try a Web search for "quadratic equation", for example. On the other hand, you should definitely learn to solve quadratic equations on your own.
Pros: There are many real life situations in which the relationship between two variables is quadratic rather than linear. So to solve these situations quadratic equations are necessary. There is a simple equation to solve any quadratic equation. Cons: Pupils who are still studying basic mathematics will not be told how to solve quadratic equations in some circumstances - when the solutions lie in the Complex field.
Factor it! Set each equal to zero! Solve
Graph the equation then find the x intercepts.
There are several ways to solve such equations: (1) Write the equation in the form polynomial = 0, and solve the left part (where I wrote "polynomial"). (2) Completing the square. (3) Use the quadratic formula. Method (3) is by far the most flexible, but in special cases methods (1) and (2) are faster to solve.