you need a velocity unless its a falling object you should type in the problem statement and you might get a better answer
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Distance = (1/2 of acceleration) x (time squared)You can change this around to solve it for acceleration or time.(Time squared) = (distance)/(half of acceleration)Time = the square root of [ (2 x distance)/(acceleration) ]Be careful . . .This is only true if the distance and the speed are both zero when the time begins.
vf2 = vi2 + 2ad, where vf is final velocity, vi is initial velocity, a is acceleration, and d is displacement. Solve for a.vf = vi + at, where t is time time. Solve for a.
a=s/t, and s=d/t, so if we substitute... a = (d/t)/t --> a = d/t2 You must know both the acceleration and time in order to solve for the distance travelled.
the general form of the units for acceleration are distance per time squared, such as m/s2.
You can use the formula for distance covered:distance = (initial velocity) x (time) + (1/2) (acceleration) (time squared) Solve for time. This assumes constant acceleration, by the way. If you assume that the initial velocity is zero, then you can omit the first term on the right. This makes the equation especially easy to solve.