So you have (4^(x-2))^(x+1)=15. Using a law of exponents (b^a)^c=b^(a*c) and 4=2^2, you get
4^((x-2)*(x+1))=15=2^(2(x-2)(x+1)).
Take log base two and use the rule about logs of products you get
2(x-2)(x+1)=Log_2(15)
Simplifying and substituting u for Log_2(15),
2x^2-2x-4=u, which means
2x^2-2x-(4+u)=0, using quadratic formula.
X=(1/4)(2(+or-)sqrt(4-4*2*(-4-u))) or
(1/2) plus or minus (1/4)(sqrt(36+8u))
Where sqrt(b) is the square root of b
Four times 3^2 minus two = 34.
192
16 - 2 = 14
(-x)2 = 3=> -x = ±√3=> x = -√3 and x = √3
4 cubed is 64, 3 squared is 9, so 55.
900 and divide10 with the power of four solve it = 90
Four times 3^2 minus two = 34.
5 to the power of 2
192
Question 3C: Four minus seven equals negative two.
16 - 2 = 14
31
Four times minus six is minus twenty four.
5/3 - 4/5 = 25/15 - 12/15 = 13/15
(-x)2 = 3=> -x = ±√3=> x = -√3 and x = √3
4 cubed is 64, 3 squared is 9, so 55.
-68 I think