2c-10
5y-4 = 7 5y = 7+4 = 11 y = 11 / 5 = 2.2
45+4 = 49 49/7=7 7*7=49-4=45 so x=7
2a*4b*(-3c) = ? 2 * 4 * -3 * a * b * c = ? -24abc
2c + 4 - 3c = -9 + c + 5 -c + 4 = c - 4 -2c = -8 2c = 8 c = 4
3c-7 = -4
It is: -28+21c = -7(4-3c)
1
2c-10
Doing it step by step:-7 = -3c + 933c = 7 + 933c = 100c= 33 1/3
3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
It is 7 - 8c.
how do i solve -3r+3r=-6(7+7r)-7(4-7r)
The solution (not sum) to the equation 21 = 3c + 6 is as follows:21 = 3c + 621 - 6 = 3c + 6 - 615 = 3c3c = 153c/3 = 21/3c = 7
4c+2 = 3c+9 4c-3c = 9-2 c = 7
-((3c - 4)(3c + 4)(2c - 5)(2c + 5))
4 + 3c = 2c + 2Subtract 4 from each side:3c = 2c - 2Subtract 2c from each side:c = -2