How do you solve linear combination 5x equals 4y-30 and 2x plus 3y equals -12?

Answer 1

Here is one possible method of solving the system: 5x = 4y - 30

2x + 3y = -12

Rewrite to line up variables:

5x - 4y = -30

2x + 3y = -12

Multiply the top equation by 2 and the bottom equation by 5:

10x - 8y = -60

10x + 15y = -60

Subtract the two equations:

-23y = 0;

So y = 0; plug back into an original equation to find x:

2x + 3(0) = -12

2x = -12

x = -6The solution to the system is x = -6 and y = 0, or the point (-6,0).