log7(117) = 2.447273291
log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107
Use the identity log(ab) = log a + log b to combine the logarithms on the left side into a single term. Then take antilogarithms (just take the log away) on both sides.
When solving this problem:1/2log7x = log720 - 2(log72 + log75)There are two things to note:lognx + logny = logn(xy)a(lognx) = lognxaUsing those two rules, we can simplify the given expression:1/2log7x = log720 - 2(log72 + log75)log7x1/2 = log720 - 2(log710)log7x1/2 = log720 - log7102log7x1/2 = log720 - log7100log7x1/2 = log7(1/5)√x = 1/5x = 1/25
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
2 log(4y) = log7(343) - log5(25)log7(343) = 3log5(25) = 22 log(4y) = 3 - 2 = 1log(4y) = 0.54y = sqrt(10)y = 0.25 sqrt(10)y = 0.79057 (rounded)
log7(117) = 2.447273291
We must assume that the question is asking us to determine the value of 'x'.log(7) + log(x) = 2log(7x) = 27x = 102 = 100x = 100/7 = 14.2857 (rounded)
x = 3*log8 = log(83) = log(512) = 2.7093 (approx)
log(10x) = 410x = 104x = 103 = 1,000
You calculate a log, you do not solve a log!
If log(Kf) = 5.167 then Kf = 105.167 = 146,983 (approx).
log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107
Use the identity log(ab) = log a + log b to combine the logarithms on the left side into a single term. Then take antilogarithms (just take the log away) on both sides.
2 log(x) + 3 log(x) = 105 log(x) = 10log(x) = 10/5 = 210log(x) = (10)2x = 100
log9(x)=2 x=9^2 x=81
k=log4 91.8 4^k=91.8 -- b/c of log rules-- log 4^k=log 91.8 -- b/c of log rules-- k*log 4=log91.8 --> divide by log 4 k=log 91.8/log 4 k= 3.260