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logx(3) = log10(7)

(assumed the common logarithm (base 10) for "log7")

x^(logx(3)) = x^(log10(7))

3 = x^(log10(7))

log10(3) = log10(x^(log10(7)))

log10(3) = log10(7)log10(x)

(log10(3)/log10(7)) = log10(x)

10^(log10(3)/log10(7)) = x

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13y ago
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Q: How do you solve log basex 3 equals log7?
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