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How do you solve 3 log of 8 equals x?
x = 3*log8 = log(83) = log(512) = 2.7093 (approx)
How do you solve 5.167 equals log Kf How to find the value of Kf?
If log(Kf) = 5.167 then Kf = 105.167 = 146,983 (approx).
How do you solve 2logx plus 3logx equals 10?
2 log(x) + 3 log(x) = 105 log(x) = 10log(x) = 10/5 = 210log(x) = (10)2x = 100
Solve e raised to the power of x equals 6?
If you want to solve ex =6, you need to take the natural log of both sides.ln ex =ln6Now we have x=ln6 which can be left that way or approximated with a calculator.ln means natural log, in case there was any question about that.The answer is about 1.79176.
How would you solve 250 to the x power equals 400000?
250(x) = 400,000 Use logs to base '10' Hence log250^(x) = log400,000 xlog250 = log 400,000 Notirce how the power (x) becomes the coefficient. This is oerfectly correct under 'log' rules. x = log 400,000 / log 250 (NOT log(250/400,000). x = 5.60206 / 2.39794 x = 2.33619689..... ~ 2.33619 to 5 d.p.
How do you solve log x - 2?
You cannot solve log x- 2 unless (i) log x - 2 is equal to some number or (ii) x is equal to some number.
How do you solve 3 log of 8 equals x?
x = 3*log8 = log(83) = log(512) = 2.7093 (approx)
How do you solve for a power in a math problem?
You have to use logarithms (logs).Here are a few handy tools:If [ C = D ], then [ log(C) = log(D) ]log(AB) = log(A) + log(B)log(A/B) = log(A) - log(B)log(Np) = p times log(N)
Solve Log f plus log 0.1 equals 6?
log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107
How do you solve log x3?
You can't solve this since it isn't an equation.There is also an ambiguity (it's hard to write math on a typewriter keyboard) - are we talking about log(x3) or maybe logx(3)?Restate the question: Simplify log(x3)Answer: 3log(x)You could explain this by saying: log(x3) = log[(x)(x)(x)] = logx + logx + logx = 3logx. The general rule is log(xn) = nlogx.
How do you solve 5.167 equals log Kf How to find the value of Kf?
If log(Kf) = 5.167 then Kf = 105.167 = 146,983 (approx).
How do you solve logx minus 3 plus log 4 equals log x?
Use the identity log(ab) = log a + log b to combine the logarithms on the left side into a single term. Then take antilogarithms (just take the log away) on both sides.
How do you solve k equals log4 91.8?
k=log4 91.8 4^k=91.8 -- b/c of log rules-- log 4^k=log 91.8 -- b/c of log rules-- k*log 4=log91.8 --> divide by log 4 k=log 91.8/log 4 k= 3.260
How do you solve log base16 8?
You divide log 8 / log 16. Calculate the logarithm in any base, but use the same base for both - for example, ln 8 / ln 16.
How do you solve 3 to the power of negative 2x plus 2 equals 81?
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
How do you solve for x.log10x equals 4?
log(10x) = 410x = 104x = 103 = 1,000
How do you solve logarithmic simultaneous equations?
That would depend a lot on the specific equations. Often the following tricks can help: (a) Take antilogarithms to get rid of the logarithms. (b) Use the properties of logarithms, especially: log(ab) = log a + log b; log(a/b) = log a - log b; log ab = b log a. (These properties work for logarithms in any base.)
