let, equation is ax2+bx+c=0
so, its solution will be
x= (-b-sqrt(b*b-4ac))/2a
x= (-b+sqrt(b*b-4ac))/2a
it is generalized equation for finding roots of Quadratic eq.
Rational.
There are many ways: one is to factorise. If the quadratic is written as ax2 + bx + c then, if b2 = 4ac, the quadratic is a perfect square. It is (x - b/2a)2
Square
By using the quadratic equation formula
By using the quadratic equation formula or by completing the square
Rational.
Yes. You can calculate the two roots of a quadratic equation by using the quadratic formula, and because there are square roots on the quadratic formula, and if the radicand is not a perfect square, so the answer to that equation has decimal.
The two solutions are coincident.
There are many ways: one is to factorise. If the quadratic is written as ax2 + bx + c then, if b2 = 4ac, the quadratic is a perfect square. It is (x - b/2a)2
square
A quadratic equation.
Yes, it won't be exact, but you can round the number to get a close estimate.
Square
By using the quadratic equation formula
By using the quadratic equation formula or by completing the square
In that case, the discriminant is not a perfect square.
The discriminant must be a perfect square or a square of a rational number.