0
You cannot.
sin(n)/n is an expression, not an equation. An expression cannot be solved.
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∙ 11y ago
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What is a quotient of 8 and a number n?
Its just 8/n or 8 divided by n. You can't solve this problem because there is no other number to simplify or solve.
Can you solve sin 2 theta equals 0?
If sin2(theta) = 0, then theta is N pi, N being any integer
In a algebra how do you solve for n in 2 times n divided by 3 equals 4?
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
How do you solve sinx divided by 1 plus cosx plus cosx divided by sinx?
sin x/(1+cos x) + cos x / sin x Multiply by sin x (1+cos x) =[(sin^2 x + cos x(1+cos x) ] / sin x (1+cos x) = [(sin^2 x + cos x + cos^2 x) ] / sin x (1+cos x) sin^2 x + cos^2 x = 1 = (1+cos x) / sin x (1+cos x) = 1/sin x
How do you solve 2 sin squared x?
Do sin(x), square it, and then multiply it by two.
How do you solve 1 over n SIN x?
sinx=n/1 (1)sinx=n/1(1) sin(-n)x=n(-n) six=6
When 475 is divided by n the quotient is 25 solve the n?
19
What is a quotient of 8 and a number n?
Its just 8/n or 8 divided by n. You can't solve this problem because there is no other number to simplify or solve.
How do you solve this equation n divided 80 equals fifty?
5x = 80
How do you solve sin x multiplied to Sin squared x is equal to 1?
sin(x)*sin2(x) = 1 so sin3(x) = 1 so that sin(x) = cuberoot(1) = 1 then x = pi/2 + n*pi where n is an integer.
Can you solve sin 2 theta equals 0?
If sin2(theta) = 0, then theta is N pi, N being any integer
When 475 is divided by n the quotent is 25 solve for n?
19
Solve sin x square root of 3 divided by 2?
1.5
In a algebra how do you solve for n in 2 times n divided by 3 equals 4?
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
Is thre ratio of Sin I to Sin R always the same?
No, the ratio of sine of the angle of incidence (I) to the sine of the angle of refraction (R) is not always the same. This ratio is constant only in a specific scenario when light passes from one medium to another with different refractive indices, as described by Snell's Law.
How do you solve sinx divided by 1 plus cosx plus cosx divided by sinx?
sin x/(1+cos x) + cos x / sin x Multiply by sin x (1+cos x) =[(sin^2 x + cos x(1+cos x) ] / sin x (1+cos x) = [(sin^2 x + cos x + cos^2 x) ] / sin x (1+cos x) sin^2 x + cos^2 x = 1 = (1+cos x) / sin x (1+cos x) = 1/sin x
How do you solve 2 sin squared x?
Do sin(x), square it, and then multiply it by two.
