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Consider angles in standard position, and note that for the equation sin θ = 0.5, the angle in the first quadrant is θ = 30°
The sin function is positive in quadrants I and II, and negative in quadrants III and IV, so there are two basic answers, one in quadrant III and another in quadrant IV.
In quadrant III, the angle is 180° + 30° = 210°
In quadrant IV, the angle is 360° - 30° = 330°
Of course, this is a wave function so there are an infinite number of answers. You can add full circles (i.e. multiples of 360°) to either of these answers to get more answers.
In quadrant III, the angles are 210°, 570°, 930°, ...
In quadrant IV, the angles are 330°, 690°, 1050°, ...
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What does the Sin of theta equal to if half of the sin of theta. what are the values of theta?
[]=theta 1. sin[]=0.5sin[] Subtract 0.5sin[] from both sides.2. 0.5sin[]=0. Divide both sides by 0.5.3. Sin[] =0.[]=0 or pi (radians)
What is 256 to the negative half power?
256 to the negative one-half power = 0.0625
Can the magnitude of a resultant vector ever be less than the magnitude of one of its components?
Yes, if the two vectors are at a sufficiently large obtuse angle.The law of cosines gives the size of the resultant.If C = A + B, where A, B, C are vectors, then C is the "resultant."The law of cosines says, he magnitudes, A,B,C, are related as follows,C2=A2+B2+2AB cosine(theta),where theta is the angle between the vectors A and B. When theta is zero, then C has the maximum length, equal to the lengths of A and B added. When theta is 180 degrees, then C has the minimum length of the difference of the length of A and of B. Somewhere in between, the length of C will equal the length of the longer component and for larger angles be smaller.To be specific, suppose that A is the longer of the two, then the resultant, C, has the same length as A at one special angle which we will call theta*.A2=A2+B2+2AB cosine(theta*)cosine(theta*)=-B/(2A).The answer to the question is then, that for angles greater than theta* the resultant is smaller than the larger component. (Greater means, of course, greater than theta* and up to 360-theta*.)Note that if we ask whether the resultant can be smaller than the smaller of the two component vectors, then the answer is again yes and the above equation holds true when A is the smaller with the condition that it is not smaller than half the length of B. When the smaller vector is less than half the length of the larger component, then the resultant may equal the length of the larger but can never be made equal to the length of the smaller component.
What is 4 divided by a negative half?
Four divided by a negative half is negative eight.
What would x is greater than or equal to negative six look like as a graph?
At negative six on the x-axis, draw a vertical line. That line will be a solid line because we have that x is greater than OR EQUAL TO negative six. Then shade the right half of the graph -- which is where x has a value that is to the right (greater than) negative six
What does the Sin of theta equal to if half of the sin of theta. what are the values of theta?
[]=theta 1. sin[]=0.5sin[] Subtract 0.5sin[] from both sides.2. 0.5sin[]=0. Divide both sides by 0.5.3. Sin[] =0.[]=0 or pi (radians)
What is the half angle formula?
The half angle formula is: sin theta/2 = ± sqrt (1 - cos theta/2)
What does a negative half times 28 equal to?
-14
What does negative three fourths divided with negative one half equal to?
3/2
What is negative one half plus four and one third equal?
negative 12 i guess
What is 256 to the negative half power?
256 to the negative one-half power = 0.0625
What is the half angle of conical pendulum of length 1 meter and mass 1 kilograms has a period of 1 second the speed of the particle in its circular motion is 1 meter per second?
T=2pieLsin(theta)/V. 1*1/2*1*pie=sin(theta). sin(theta)=0.1591. (theta)=sin-1(0.1591). (theta)=9.1 degree. half angle=9.15degree
What is negative one half times zero?
Anything multiplied by zero is equal to zero.
How do you solve the equation cos2x plus 20 equals negative half?
Better formatting is cos(2x+20)=-0.5
How do you solve negative x equals one half?
-x = 1/2Multiply each side by -1 :x = -1/2
Can the magnitude of a resultant vector ever be less than the magnitude of one of its components?
Yes, if the two vectors are at a sufficiently large obtuse angle.The law of cosines gives the size of the resultant.If C = A + B, where A, B, C are vectors, then C is the "resultant."The law of cosines says, he magnitudes, A,B,C, are related as follows,C2=A2+B2+2AB cosine(theta),where theta is the angle between the vectors A and B. When theta is zero, then C has the maximum length, equal to the lengths of A and B added. When theta is 180 degrees, then C has the minimum length of the difference of the length of A and of B. Somewhere in between, the length of C will equal the length of the longer component and for larger angles be smaller.To be specific, suppose that A is the longer of the two, then the resultant, C, has the same length as A at one special angle which we will call theta*.A2=A2+B2+2AB cosine(theta*)cosine(theta*)=-B/(2A).The answer to the question is then, that for angles greater than theta* the resultant is smaller than the larger component. (Greater means, of course, greater than theta* and up to 360-theta*.)Note that if we ask whether the resultant can be smaller than the smaller of the two component vectors, then the answer is again yes and the above equation holds true when A is the smaller with the condition that it is not smaller than half the length of B. When the smaller vector is less than half the length of the larger component, then the resultant may equal the length of the larger but can never be made equal to the length of the smaller component.
How do you solve y equals negative one half multiplied by x minus twelve?
technically it's already solved, you just have to graph it i guess.
