[]=theta 1. sin[]=0.5sin[] Subtract 0.5sin[] from both sides.
2. 0.5sin[]=0. Divide both sides by 0.5.
3. Sin[] =0.
[]=0 or pi (radians)
sin(0)=0 and sin(very large number) is approximately equal to that same very large number.
It is not! So the question is irrelevant.
The equation cannot be proved because of the scattered parts.
Any value for which sin(theta) = 0, i.e. theta = N*180, N being an Integer.
In a Right Triangle SINE Theta is equal to the: (Length of opposite side) / (Length of Hypotenuse).
sin(0)=0 and sin(very large number) is approximately equal to that same very large number.
It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!
It is not! So the question is irrelevant.
because sin(2x) = 2sin(x)cos(x)
answer is 2.34 degrees answer is 2.34 degrees
The equation cannot be proved because of the scattered parts.
Any value for which sin(theta) = 0, i.e. theta = N*180, N being an Integer.
assuming that you mean what is theta if sin 4 theta = 0 then then theta=0, 0.25pi, 0.5pi, 0.75pi... if not then without additional information the best answer you can get is sin4theta=sin4theta
The half angle formula is: sin theta/2 = ± sqrt (1 - cos theta/2)
4 sin(theta) = 2 => sin(theta) = 2/4 = 0.5. Therefore theta = 30 + k*360 degrees or 150 + k*360 degrees where k is any integer.
-0.5736
you have to do the arcsin which is sin-1 on your calculator. i have not met anyone in my life who can do sin or arcsin in their head. not even my college teachers. your theta is equal to 20degrees