(a + b)3 = a3 + 3a2b + 3ab2 + b3
(8m+6)
that;s so simple . try it
Binomial Expansion makes it easier to solve an equation. It brings an equation of something raised to a power down to a solveable equation without parentheses.
The cube of a binomial is the cube of two terms separated by an addition or subtraction sign, such as (2a + 3b) or (ab - cd).For example, (2x - 5y)3 = 8x3 - 40x2y + 50xy2 - 20x2y + 100xy2 - 125y3.The detailed method of expanding this binomial is : (2x - 5y)3 = (2x - 5y)(2x - 5y)(2x - 5y) = (4x2 - 20xy + 25y2)(2x - 5y) = 8x3 - 40x2y + 50xy2 - 20x2y + 100xy2 - 125y3
The cube of the binomial ( (4k - 7q) ) can be calculated using the formula for the cube of a binomial, which is ( (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3 ). Here, ( a = 4k ) and ( b = 7q ). Applying the formula, we get: [ (4k - 7q)^3 = (4k)^3 - 3(4k)^2(7q) + 3(4k)(7q)^2 - (7q)^3. ] This simplifies to: [ 64k^3 - 84k^2q + 147kq^2 - 343q^3. ]
Consider a binomial (a+b). The cube of the binomial is given as =(a+b)3 =a3 + 3a2b + 3ab2 + b3.
In Step 1 and the final step to solve the 1x1, you use a algorithm, that algorithm is U Ui.
99x99x99
To calculate the cube of a binomial, you can multiply the binomial with itself first (to get the square), then multiply the square with the original binomial (to get the cube). Since cubing a binomial is quite common, you can also use the formula: (a+b)3 = a3 + 3a2b + 3ab2 + b3 ... replacing "a" and "b" by the parts of your binomial, and doing the calculations (raising to the third power, for example).
step 1 the daisy
(8m+6)
jb+++u
that;s so simple . try it
STEPS : FIRST TERM = the cube of the first term SECOND TERM=three times the product of the squareof first term and second term THIRD TERM=three times the product of first term and square of second term FOURTH TERM=THE CUBE OF THE LAST TERM ..
STEPS : FIRST TERM = the cube of the first term SECOND TERM=three times the product of the squareof first term and second term THIRD TERM=three times the product of first term and square of second term FOURTH TERM=THE CUBE OF THE LAST TERM ..
STEPS : FIRST TERM = the cube of the first term SECOND TERM=three times the product of the squareof first term and second term THIRD TERM=three times the product of first term and square of second term FOURTH TERM=THE CUBE OF THE LAST TERM ..
Finding the cube root of 3 would not have helped.