To calculate the cube of a binomial, you can multiply the binomial with itself first (to get the square), then multiply the square with the original binomial (to get the cube). Since cubing a binomial is quite common, you can also use the formula:
(a+b)3 = a3 + 3a2b + 3ab2 + b3
... replacing "a" and "b" by the parts of your binomial, and doing the calculations (raising to the third power, for example).
Consider a binomial (a+b). The cube of the binomial is given as =(a+b)3 =a3 + 3a2b + 3ab2 + b3.
Since 33 is 3*3*3, the cube of 3 is 27.
x4
1.442249571.4422495703074083
let binomial be (a + b)now (a+b)3 will be (a+b)(a+b)2 = (a+b)(a2 + 2ab+ b2) = a(a2+ 2ab+ b2) + b(a2 + 2ab+ b2) = a3+ 2a2b+ ab2 + a2b + 2ab2 + b3 = a3+ 2a2b+ ab2 + a2b + 2ab2 + b3 = a3 +3a2b + 3ab2 +b3 hope it helped... :D
Consider a binomial (a+b). The cube of the binomial is given as =(a+b)3 =a3 + 3a2b + 3ab2 + b3.
The cube of the binomial ( (4k - 7q) ) can be calculated using the formula for the cube of a binomial, which is ( (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3 ). Here, ( a = 4k ) and ( b = 7q ). Applying the formula, we get: [ (4k - 7q)^3 = (4k)^3 - 3(4k)^2(7q) + 3(4k)(7q)^2 - (7q)^3. ] This simplifies to: [ 64k^3 - 84k^2q + 147kq^2 - 343q^3. ]
99x99x99
(a + b)3 = a3 + 3a2b + 3ab2 + b3
(8m+6)
jb+++u
that;s so simple . try it
The cube of a binomial is the cube of two terms separated by an addition or subtraction sign, such as (2a + 3b) or (ab - cd).For example, (2x - 5y)3 = 8x3 - 40x2y + 50xy2 - 20x2y + 100xy2 - 125y3.The detailed method of expanding this binomial is : (2x - 5y)3 = (2x - 5y)(2x - 5y)(2x - 5y) = (4x2 - 20xy + 25y2)(2x - 5y) = 8x3 - 40x2y + 50xy2 - 20x2y + 100xy2 - 125y3
As a binomial it is, surprisingly, x + 3.
(ax + b)^3 = a^3*x^3 + 3*a^2*x^2*b + 3*a*x*b^2 + b^3. Sorry, but it is so clumsy doing this without superscripts!
A binomial multiplied to itself 3 times. Example (x + 2)3 = (x + 2) (x + 2) (x + 2) This would equal x3 + 4x2 + 8x + 8
First, look at the given problem. eg. (8n-3)^3. Mark the first term (8n) A then mark the second term (-3) B. Do this formula. (a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3