To calculate the cube of a binomial, you can multiply the binomial with itself first (to get the square), then multiply the square with the original binomial (to get the cube). Since cubing a binomial is quite common, you can also use the formula:
(a+b)3 = a3 + 3a2b + 3ab2 + b3
... replacing "a" and "b" by the parts of your binomial, and doing the calculations (raising to the third power, for example).
Consider a binomial (a+b). The cube of the binomial is given as =(a+b)3 =a3 + 3a2b + 3ab2 + b3.
Since 33 is 3*3*3, the cube of 3 is 27.
x4
1.442249571.4422495703074083
let binomial be (a + b)now (a+b)3 will be (a+b)(a+b)2 = (a+b)(a2 + 2ab+ b2) = a(a2+ 2ab+ b2) + b(a2 + 2ab+ b2) = a3+ 2a2b+ ab2 + a2b + 2ab2 + b3 = a3+ 2a2b+ ab2 + a2b + 2ab2 + b3 = a3 +3a2b + 3ab2 +b3 hope it helped... :D
Consider a binomial (a+b). The cube of the binomial is given as =(a+b)3 =a3 + 3a2b + 3ab2 + b3.
The cube of the binomial ( (4k - 7q) ) can be calculated using the formula for the cube of a binomial, which is ( (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3 ). Here, ( a = 4k ) and ( b = 7q ). Applying the formula, we get: [ (4k - 7q)^3 = (4k)^3 - 3(4k)^2(7q) + 3(4k)(7q)^2 - (7q)^3. ] This simplifies to: [ 64k^3 - 84k^2q + 147kq^2 - 343q^3. ]
(a + b)3 = a3 + 3a2b + 3ab2 + b3
99x99x99
(8m+6)
jb+++u
The cube of a binomial is the cube of two terms separated by an addition or subtraction sign, such as (2a + 3b) or (ab - cd).For example, (2x - 5y)3 = 8x3 - 40x2y + 50xy2 - 20x2y + 100xy2 - 125y3.The detailed method of expanding this binomial is : (2x - 5y)3 = (2x - 5y)(2x - 5y)(2x - 5y) = (4x2 - 20xy + 25y2)(2x - 5y) = 8x3 - 40x2y + 50xy2 - 20x2y + 100xy2 - 125y3
that;s so simple . try it
(ax + b)^3 = a^3*x^3 + 3*a^2*x^2*b + 3*a*x*b^2 + b^3. Sorry, but it is so clumsy doing this without superscripts!
As a binomial it is, surprisingly, x + 3.
The cube of a binomial refers to the expression obtained when a binomial is raised to the third power, typically represented as ((a + b)^3). It can be expanded using the formula ((a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3). This expansion includes the individual cubes of the terms and three times the product of each term squared multiplied by the other term. The formula can also be applied to binomials in the form ((a - b)^3), with a similar expansion that incorporates negative signs appropriately.
A binomial multiplied to itself 3 times. Example (x + 2)3 = (x + 2) (x + 2) (x + 2) This would equal x3 + 4x2 + 8x + 8