The expression you presented is not an equation.
Do you mean ax2 + bx = c?
Do you mean to solve it for x?
I'm assuming that's the case, but you need to be more clear on your question.
To solve for x then, the technique to use is called completing the square:
ax2 + bx = c
Multiply both sides by a:
a2x2 + abx = ac
Add the square of b/2 to both sides:
a2x2 + abx + (b/2)2 = ac + (b/2)2
We now have a perfect square on the left, simplify:
(ax + b/2)2 = ac + b2 / 4
(ax + b/2)2 = (4ac + b2) / 4
And now solve for x:
ax + b/2 = ±[(4ac + b2) / 4]1/2
ax + b/2 = ± √(4ac + b2) / 2
ax = [-b ± √(4ac + b2)] / 2
x = [-b ± √(4ac + b2)] / 2a
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Solve the equation for y. This will give you an equation similar to y = ax + b, where a is the slope, and b is the y-intercept.
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
To solve something you need an equation (or inequality). An equation comprises two expressions with an equality sign between them. Here, there is only one expression: the "square of binomial". So, you cannot solve it.You expand the expression as follows:(ax + b)^2 = a^2x^2 + 2abx + b^2