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The expression you presented is not an equation.
Do you mean ax2 + bx = c?
Do you mean to solve it for x?
I'm assuming that's the case, but you need to be more clear on your question.
To solve for x then, the technique to use is called completing the square:
ax2 + bx = c
Multiply both sides by a:
a2x2 + abx = ac
Add the square of b/2 to both sides:
a2x2 + abx + (b/2)2 = ac + (b/2)2
We now have a perfect square on the left, simplify:
(ax + b/2)2 = ac + b2 / 4
(ax + b/2)2 = (4ac + b2) / 4
And now solve for x:
ax + b/2 = ±[(4ac + b2) / 4]1/2
ax + b/2 = ± √(4ac + b2) / 2
ax = [-b ± √(4ac + b2)] / 2
x = [-b ± √(4ac + b2)] / 2a
What else can I help you with?
What To solve an equation of the form ax you need to divide by the?
Co variable
How can you solve this equation ax plus ax2-bx-bx2?
4
How do you solve the B in Ax plus By equals C?
To solve for B in the equation ( Ax + By = C ), you first isolate the term involving B. Rearranging gives ( By = C - Ax ). Then, divide both sides by y (assuming y is not zero) to solve for B: ( B = \frac{C - Ax}{y} ).
What do you need to divide by to solve the equation of the form axb?
To solve an equation of the form ( ax = b ), you need to divide both sides of the equation by ( a ) (assuming ( a \neq 0 )). This gives you ( x = \frac{b}{a} ), isolating ( x ) on one side of the equation.
What is the first step in solving a quadratic equation of the form (ax plus b)2c?
The first step in solving a quadratic equation of the form ((ax + b)^2 = c) is to take the square root of both sides to eliminate the square. This gives you two possible equations: (ax + b = \sqrt{c}) and (ax + b = -\sqrt{c}). From there, you can isolate (ax) and solve for (x) by subtracting (b) and then dividing by (a).
What To solve an equation of the form ax you need to divide by the?
Co variable
Solve the equation ax-b equals c for x?
ax - b = c ax = b + c x = (b + c)/a
What is a-bxc in math?
it is the slope formula in the equation it is the slope formula in the equation
What are all of the multiplicative identities?
AxB=BxA (AxB)xC=Ax(BxC) Ax(B+C)=AxB+AxC Ax1=A Ax0=0
How can you solve this equation ax plus ax2-bx-bx2?
4
How do you solve the B in Ax plus By equals C?
To solve for B in the equation ( Ax + By = C ), you first isolate the term involving B. Rearranging gives ( By = C - Ax ). Then, divide both sides by y (assuming y is not zero) to solve for B: ( B = \frac{C - Ax}{y} ).
The equation AX plus BY is the general equation for a?
AX + BY is not an equation .AX + BY + C = 0is the general equation for a straight line.
To solve an equation of the form ax b you need to divide by the what?
I believe its coefficient.
What do you need to divide by to solve the equation of the form axb?
To solve an equation of the form ( ax = b ), you need to divide both sides of the equation by ( a ) (assuming ( a \neq 0 )). This gives you ( x = \frac{b}{a} ), isolating ( x ) on one side of the equation.
How can we find the coordinates of x in the intersection of line and curve?
For example, the equation of a line: y = ax + b. the equation of a curve: y = cx2 + dx + e ax + b = cx2 + dx + e (solve for x)
How do you solve for x using a quadratic equation?
For an equation of the form ax² + bx + c = 0 you can find the values of x that will satisfy the equation using the quadratic equation: x = [-b ± √(b² - 4ac)]/2a
What is the first step in solving a quadratic equation of the form (ax plus b)2c?
The first step in solving a quadratic equation of the form ((ax + b)^2 = c) is to take the square root of both sides to eliminate the square. This gives you two possible equations: (ax + b = \sqrt{c}) and (ax + b = -\sqrt{c}). From there, you can isolate (ax) and solve for (x) by subtracting (b) and then dividing by (a).
