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The expression you presented is not an equation.
Do you mean ax2 + bx = c?
Do you mean to solve it for x?
I'm assuming that's the case, but you need to be more clear on your question.
To solve for x then, the technique to use is called completing the square:
ax2 + bx = c
Multiply both sides by a:
a2x2 + abx = ac
Add the square of b/2 to both sides:
a2x2 + abx + (b/2)2 = ac + (b/2)2
We now have a perfect square on the left, simplify:
(ax + b/2)2 = ac + b2 / 4
(ax + b/2)2 = (4ac + b2) / 4
And now solve for x:
ax + b/2 = ±[(4ac + b2) / 4]1/2
ax + b/2 = ± √(4ac + b2) / 2
ax = [-b ± √(4ac + b2)] / 2
x = [-b ± √(4ac + b2)] / 2a
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What To solve an equation of the form ax you need to divide by the?
Co variable
How can you solve this equation ax plus ax2-bx-bx2?
4
What is the y intercept of the graph of -5x plus 10y equals 20?
Solve the equation for y. This will give you an equation similar to y = ax + b, where a is the slope, and b is the y-intercept.
How do you solve for roots in a parabola?
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
How do you solve square of binomial?
To solve something you need an equation (or inequality). An equation comprises two expressions with an equality sign between them. Here, there is only one expression: the "square of binomial". So, you cannot solve it.You expand the expression as follows:(ax + b)^2 = a^2x^2 + 2abx + b^2
What To solve an equation of the form ax you need to divide by the?
Co variable
Solve the equation ax-b equals c for x?
ax - b = c ax = b + c x = (b + c)/a
What is a-bxc in math?
it is the slope formula in the equation it is the slope formula in the equation
What are all of the multiplicative identities?
AxB=BxA (AxB)xC=Ax(BxC) Ax(B+C)=AxB+AxC Ax1=A Ax0=0
How can you solve this equation ax plus ax2-bx-bx2?
4
The equation AX plus BY is the general equation for a?
AX + BY is not an equation .AX + BY + C = 0is the general equation for a straight line.
To solve an equation of the form ax b you need to divide by the what?
I believe its coefficient.
How can we find the coordinates of x in the intersection of line and curve?
For example, the equation of a line: y = ax + b. the equation of a curve: y = cx2 + dx + e ax + b = cx2 + dx + e (solve for x)
How do you solve for x using a quadratic equation?
For an equation of the form ax² + bx + c = 0 you can find the values of x that will satisfy the equation using the quadratic equation: x = [-b ± √(b² - 4ac)]/2a
What is the y intercept of the graph of -5x plus 10y equals 20?
Solve the equation for y. This will give you an equation similar to y = ax + b, where a is the slope, and b is the y-intercept.
How too solve linear equations?
First rearrange the linear equation to the form ax + b = cThen subtract b from both sides: ax = c - b Divide both sides by a: x = (c - b)/a
How do you solve for roots in a parabola?
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
