The expression you presented is not an equation.
Do you mean ax2 + bx = c?
Do you mean to solve it for x?
I'm assuming that's the case, but you need to be more clear on your question.
To solve for x then, the technique to use is called completing the square:
ax2 + bx = c
Multiply both sides by a:
a2x2 + abx = ac
Add the square of b/2 to both sides:
a2x2 + abx + (b/2)2 = ac + (b/2)2
We now have a perfect square on the left, simplify:
(ax + b/2)2 = ac + b2 / 4
(ax + b/2)2 = (4ac + b2) / 4
And now solve for x:
ax + b/2 = ±[(4ac + b2) / 4]1/2
ax + b/2 = ± √(4ac + b2) / 2
ax = [-b ± √(4ac + b2)] / 2
x = [-b ± √(4ac + b2)] / 2a
Co variable
4
To solve for B in the equation ( Ax + By = C ), you first isolate the term involving B. Rearranging gives ( By = C - Ax ). Then, divide both sides by y (assuming y is not zero) to solve for B: ( B = \frac{C - Ax}{y} ).
To solve an equation of the form ( ax = b ), you need to divide both sides of the equation by ( a ) (assuming ( a \neq 0 )). This gives you ( x = \frac{b}{a} ), isolating ( x ) on one side of the equation.
The first step in solving a quadratic equation of the form ((ax + b)^2 = c) is to take the square root of both sides to eliminate the square. This gives you two possible equations: (ax + b = \sqrt{c}) and (ax + b = -\sqrt{c}). From there, you can isolate (ax) and solve for (x) by subtracting (b) and then dividing by (a).
Co variable
ax - b = c ax = b + c x = (b + c)/a
it is the slope formula in the equation it is the slope formula in the equation
AxB=BxA (AxB)xC=Ax(BxC) Ax(B+C)=AxB+AxC Ax1=A Ax0=0
4
AX + BY is not an equation .AX + BY + C = 0is the general equation for a straight line.
I believe its coefficient.
To solve an equation of the form ( ax = b ), you need to divide both sides of the equation by ( a ) (assuming ( a \neq 0 )). This gives you ( x = \frac{b}{a} ), isolating ( x ) on one side of the equation.
For example, the equation of a line: y = ax + b. the equation of a curve: y = cx2 + dx + e ax + b = cx2 + dx + e (solve for x)
For an equation of the form ax² + bx + c = 0 you can find the values of x that will satisfy the equation using the quadratic equation: x = [-b ± √(b² - 4ac)]/2a
Solve the equation for y. This will give you an equation similar to y = ax + b, where a is the slope, and b is the y-intercept.
If angles AXC and BXC form a linear pair, it means they are adjacent angles that share a common vertex (point X) and their non-common sides (rays AX and BX) form a straight line. Consequently, the measures of angles AXC and BXC add up to 180 degrees. This property is fundamental in geometry, indicating that the two angles are supplementary.