sqrtx=20
to get rid of the square root you square both sides so sqrt(x)^2=x and (20)^2=400
x=400
87
Take the square root of both sides. x=the square root of 10. It is an irrational number. Approximately 3.15
This question cannot be answered. You will have to give me the number to the square root. * * * * * a = ±sqrt(c^2 - b^2)
Square root both sides and then x = 4
No, pi is not used to solve a square root problem.
If x equals the square root of ...., then you already have solved for x
87
68
It depends on which variable you wish to solve for.
Take the square root of both sides. x=the square root of 10. It is an irrational number. Approximately 3.15
This question cannot be answered. You will have to give me the number to the square root. * * * * * a = ±sqrt(c^2 - b^2)
Square root both sides and then x = 4
x2=-81take the square root of both sidessince 81 is negative you need to take 81 times i when i=-1 then solve as the square root of 81. your answer is x=9i
No, pi is not used to solve a square root problem.
Square root of 6.25 equals ± 2.5
Yes and x = 2+square root of 6 or x = 2-square root of 6
The square root of four twenty-fifths, is two fifths, because of the fact that the square root of four is two and the square root of twenty-five is five.