Let the number be x:
x+x/2 = 36
Multiply all terms by 2 to eliminate the fraction:
2x+x = 72
3x = 72
Divide both sides by 3 to find the value of:
x = 24
Check: 24+24/2 = 36
The equation for three times the sum of a number ( x ) and five times the number can be expressed as ( 3(x + 5x) = 36 ). Simplifying this gives ( 3(6x) = 36 ), or ( 18x = 36 ). To solve for ( x ), divide both sides by 18, resulting in ( x = 2 ).
"the sum of 2" and "twice" "a number" "is" "36"2+2x=36 â–
1/2x+6=1/3x 3x+36=2x 3x=2x-36 x=-36
The half of 36 is 18.
44. Also works for 36, 63.
The equation for three times the sum of a number ( x ) and five times the number can be expressed as ( 3(x + 5x) = 36 ). Simplifying this gives ( 3(6x) = 36 ), or ( 18x = 36 ). To solve for ( x ), divide both sides by 18, resulting in ( x = 2 ).
"the sum of 2" and "twice" "a number" "is" "36"2+2x=36 â–
36 is a perfect square number.
1/2x+6=1/3x 3x+36=2x 3x=2x-36 x=-36
The half of 36 is 18.
the sum of 8 and 4 times a number is 36
44. Also works for 36, 63.
Because the sum of its proper divisors is greater than 36.
36+37=73
-20 because -20 + 36 = 16
Assuming you mean how to solve what three consecutive numbers sum to some value: Divide the sum by three to get the middle number. The other two numbers are one less than this and one more than it. example: Which three consecutive numbers sum to 108? 108 ÷ 3 = 36 → The other two numbers are 36 - 1 = 35 and 36 + 1 = 37 → The three numbers are 35, 36, 37. 35 + 36 + 37 = 108 as required.
Let the number x and so: 1/2x +6 = 1/3x with the value of x being -36