Te sequence is defined by
t(n) = 12 - 3n where n = 1, 2, 3, ...
The sum of the first k terms of this sequence is 12k - 3*k*(k+1)/2
Therefore 12k - 3k*(k+1)/2 = 0
12k = 3k*(k+1)/2
8 = k+1
so that k = 7
To solve this arithmetic series problem, you can use the formula: Sn = (n/2) * (2a + (n-1)d), where Sn is the sum of the series, a is the first term, d is the common difference, and n is the number of terms. Substituting the given values, we have: 0 = (n/2) * (2(9) + (n-1)(-3)). Simplifying, we get: 0 = (n/2) * (18 - 3n + 3). Rearranging and simplifying further, we have: 0 = 9n^2 - 27n. Factoring out n, we get: n(9n - 27) = 0. Therefore, either n = 0 or n = 3. Since the number of terms cannot be zero, the number of terms in the series is 3.
From the information given, all that can be said is that it will be a negative number.
It's technically called an arithmetic sequence
A single number, such as 11111, cannot define an arithmetic sequence. On the other hand, it can be the first element of any kind of sequence. On the other hand, if the question was about ``1, 1, 1, 1, 1'' then that is an arithmetic sequence as there is a common difference of 0 between each term.
The quotient is the answer in a division problem.
The difference is nthe number answer after subtracting.
The difference between each number in an arithmetic series
could also be negative
6
From the information given, all that can be said is that it will be a negative number.
arithmetic starts with m while number theory starts with n
The numbers are in an arithmetic sequence (common difference = 6). Since there are 5 of them, their mean is the middle number: 79.
You subtract any two adjacent numbers in the sequence. For example, in the sequence (1, 4, 7, 10, ...), you can subtract 4 - 1, or 7 - 4, or 10 - 7; in any case you will get 3, which is the common difference.
It's technically called an arithmetic sequence
Problems that have only numbers are problems in arithmetic.
A single number, such as 11111, cannot define an arithmetic sequence. On the other hand, it can be the first element of any kind of sequence. On the other hand, if the question was about ``1, 1, 1, 1, 1'' then that is an arithmetic sequence as there is a common difference of 0 between each term.
The quotient is the answer in a division problem.
The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.