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What else can I help you with?
How do you solve for -x to the fourth 1?
The question cannot be answered because:there is no equation to solve. It may be assumed that it is "= 1" but that is not certain.it is not clear whether the question refers to (-x)4 or -(x4).
Solve for x if x4 38?
if you are meaning 4x=38, then the answer is 9.5
How do you solve 4 is what precent of 50?
2% (50 x4) / 100
How do you solve x4-6x2-12?
To solve the equation ( x^4 - 6x^2 - 12 = 0 ), you can make a substitution by letting ( y = x^2 ). The equation then becomes ( y^2 - 6y - 12 = 0 ). You can solve this quadratic equation using the quadratic formula ( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). After finding the values of ( y ), substitute back ( y = x^2 ) to find the values of ( x ).
What are some ways to solve an equation?
solve it
How do you solve for -x to the fourth 1?
The question cannot be answered because:there is no equation to solve. It may be assumed that it is "= 1" but that is not certain.it is not clear whether the question refers to (-x)4 or -(x4).
What is the answer to the equation 5 (-3) x4?
There is no answer because without an equality sign it is not an equation
Solve for x if x4 38?
if you are meaning 4x=38, then the answer is 9.5
How do you solve 4 is what precent of 50?
2% (50 x4) / 100
How do you solve x4-6x2-12?
To solve the equation ( x^4 - 6x^2 - 12 = 0 ), you can make a substitution by letting ( y = x^2 ). The equation then becomes ( y^2 - 6y - 12 = 0 ). You can solve this quadratic equation using the quadratic formula ( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). After finding the values of ( y ), substitute back ( y = x^2 ) to find the values of ( x ).
Can you solve for a variable in an equation?
Sure. You can always 'solve for' a variable, and if it happens to be the only variable in the equation, than that's how you solve the equation.
Do you answer an equation?
you don't answer an equation, you solve an equation
How do you solve the difference of the product 4 times a number and 23 is 343?
343-23=320 320/4=80 or x4+23=343 x4+23-23=343-23 x4=320 x4/4=320/4 x=80
What are some ways to solve an equation?
solve it
What equation do you get when you solve 2x plus 3y 12 for y?
If you solve such an equation for "y", you get an equation in the slope-intercept form.
Graph the solution set to each compound x-1 and x4?
Neither x-1 nor x4 is an equation or an inequality. There is, therefore, nothing to graph anything.
Can you solve for a variable in an expression or equation?
you can only solve for one in an equation so it can equal something
