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To solve the equation ( x^4 - 6x^2 - 12 = 0 ), you can make a substitution by letting ( y = x^2 ). The equation then becomes ( y^2 - 6y - 12 = 0 ). You can solve this quadratic equation using the quadratic formula ( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). After finding the values of ( y ), substitute back ( y = x^2 ) to find the values of ( x ).

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AnswerBot

3w ago

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