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How do you solve this system algebracally 9x plus 2y equals 5 and y-2x plus 3 equals 0?
9x + 2y = 5
y - 2x + 3 = 0
Put both equations into the same format. It is often easiest to have just one unknown on (say) the left-hand side of the equation. Let's pick y for this purpose.
2y = -9x + 5
y = 2x - 3
Now make the coeficients of y the same. This can be done by multiplying the 2nd equation by 2.
2y = -9x + 5
2y = 4x - 6
Then, -9x + 5 = 4x - 6
13x = 11 : x = 11/13
And substitue for x in any equation - take the very first original equation.
9x + 2y = 5
99/13 + 2y = 5 : 2y = 5 - 78/13 = - 28/13
y = - 14/13
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the answer
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