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The answer depends on the nature of the function that defines the curve whose slope you want.
If the function f(x) is differentiable, its slope is f'(x) = df(x)/dx and the value of the slope at a point when x = x0 is f'(x0), obtained by substituting x0 for x in f'(x).
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How do you solve rise over run?
You need to find the slope in the equation.
What is the slope of a gragh with the equation -3x plus 2?
Y = - 3X + 2 - 3 is the slope here ============== Whenever, you want to find the slope of a line, you first solve for the y = mx + b form of the function and then "m" is your slope.
How do you find slope for an equation with no y?
you must solve for y, using the equatin y=mx+b
How can you use the initial value theorem to solve for the initial slope of a function?
I suggest: - Take the derivative of the function - Find its initial value, which could be done with the initial value theorem That value is the slope of the original function.
How do you Convert an equation into slope-intercept form?
Solve it for 'y' .
How do you solve rise over run?
You need to find the slope in the equation.
What is an equation of the line that passes through the point 50 and is perpendicular to the line 5x 6y24 express your answer in slope-intercept form?
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
What is the slope of a gragh with the equation -3x plus 2?
Y = - 3X + 2 - 3 is the slope here ============== Whenever, you want to find the slope of a line, you first solve for the y = mx + b form of the function and then "m" is your slope.
How do you find slope for an equation with no y?
you must solve for y, using the equatin y=mx+b
How can you use the initial value theorem to solve for the initial slope of a function?
I suggest: - Take the derivative of the function - Find its initial value, which could be done with the initial value theorem That value is the slope of the original function.
How do you solve slope and equations?
The slope is the rise/over run of a line. The equation of a line is usually written in the form y=mx+b where m is the slope and b is the y-intercept. To find the slope, you can take two points on a line, find how much the line goes up (or down) between the two, and divide it by how much the lines moves to the right. Usually the slope is left in the simplest fraction form.
What is the slope of the line that goes through the points 2 5 and 1 -3?
To solve this, use the slope formula. the slope formula is m = (y2 - y1) / (x2 - x1) Therefore, m = ( -3 - 5)/ (1-2) If you solve this, you will get 8. So the slope of the line is 8.
How do you Convert an equation into slope-intercept form?
Solve it for 'y' .
How do you solve a slope?
You take the change in Y or dy and divide it by the change in X or dx. Slope equals dy/dx.
How do you solve the slope y equals 2x plus 8?
8
How do you find slope intercept form out of a equation equal to x?
The simplest way is to change the subject of the formula so that it is in the form y = mx + c. There are alternatives, but a lot more work. Differentiate the equation equal to x, and solve for dy/dx (that is the slope). Substitute x = 0 in the original equation and solve for y (that is the intercept).
Find the slope of a line passing through the points 2 -5 and -1 -8?
Use the equation y1-y2/x1-x2 PLug in the numbers -5--8/2--1 Solve 3/3 The Slope is 1
