Does this mean w^2 + w -30 = 0 ? If so, w = 5 or -6
w2+18w+77 = (w+7)(w+11) when factored
x = W2 - V and you cannot get any further than that since neither W nor V are known.
w2-3w = 0 w(w-3) = 0 w = 3 or w = 0
l + w = 110 so l = 110 - w, making lw = 110w - w2 which equals 2800. This rearranges to w2 - 110w + 2800 = 0. The factors of this are (w - 70)(w - 40) so w = 40 and l = 70. Factors of 2800 are 2 x 1400, 4 x 700, 5 x 560, 7 x 400, 8 x 350, 10 x 280, 20 x 140, 25 x 112, 70 x 40
It is either a linear equation in a variable ww or a quadratic equation in a variable w, (with ww denoting w2).
Does this mean w^2 + w -30 = 0 ? If so, w = 5 or -6
w2+18w+77 = (w+7)(w+11) when factored
It is not possible to solve for a value of X since there are three unknowns, X, v and W and only one equation. All that can be done is to make x the subject of the equation - that is, to express X in terms of the other two variables. X2 - v = W2 X2 = W2 + v X = +/- sqrt(W2 + v)
Oh, what a happy little math problem we have here! To factor w^2 + 8w + 12, we're looking for two numbers that multiply to 12 and add up to 8. Those numbers are 2 and 6. So, we can rewrite the equation as (w + 2)(w + 6). Just like that, we've created a beautiful factorization!
x = W2 - V and you cannot get any further than that since neither W nor V are known.
w2-3w = 0 w(w-3) = 0 w = 3 or w = 0
(w + 7)(w - 2)
w^2 +/- 28w - 1 is an expression, not an equation. Expressions do not have solutions.
(w² + 5w + 6) / (w² - w - 12)= [(w + 2)(w + 3)] / [(w - 4)(w + 3)]= (w + 2) / (w - 4)
The square root of 150 will be between 12 and 13, closer to 12.
l + w = 110 so l = 110 - w, making lw = 110w - w2 which equals 2800. This rearranges to w2 - 110w + 2800 = 0. The factors of this are (w - 70)(w - 40) so w = 40 and l = 70. Factors of 2800 are 2 x 1400, 4 x 700, 5 x 560, 7 x 400, 8 x 350, 10 x 280, 20 x 140, 25 x 112, 70 x 40