0
x2 + 4x = 1
x2 + 4x - 1 = 0
in the quadratic formula (b2+- Sqr(4ac))/2a,
a = 1
b = 4
c = -1
so x = 8 +- i
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Solve x2 plus 4x plus 3 equals 0?
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
How do you solve the equation. X2 plus y2 plus z2 - 4x plus 4y plus 2z plus 5 equals 0 x2 plus y2 plus z2 equals 4?
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X2 plus y2 plus 4x - 2y - 5 equals 0?
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What is x2 plus 4x plus 4 equals 25?
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
How do you solve x2 plus 4 equals 4x?
Rearrange: x2 - 4x + 4 = 0Factorise: (x - 2)(x - 2) = 0x = 2Check: 4 + 4 = 4 x 2? Sure does, job done.
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