x3-2x2-5x+6=0 (1.) First divide by (x-1) using long division. This is one of the values of x : x-1=0, x=1 (2.) After division, you will be left with x2-x-6=0 (3.) You then use the quadratic formula to find the remaining values of x.
[-b+-(b2-4ac)]/(2a) (4.) Adding from step (1.), the answer is x = 1, 3, -2
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
IMPOSSIBLE
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
No.
It is x = -5
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
IMPOSSIBLE
cube root of 216 = 6 > X= 6
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
No.
y2=x3+3x2
It is x = -5
No, it is not.
(xn+2-1)/(x2-1)
x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
Since that isn't an equation, there is really nothing to solve.