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x3-2x2-5x+6=0 (1.) First divide by (x-1) using long division. This is one of the values of x : x-1=0, x=1 (2.) After division, you will be left with x2-x-6=0 (3.) You then use the quadratic formula to find the remaining values of x.

[-b+-(b2-4ac)]/(2a) (4.) Adding from step (1.), the answer is x = 1, 3, -2

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Q: How do you solve x3 -2x2-5x plus 6 equals 0?
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