x3-2x2-5x+6=0 (1.) First divide by (x-1) using long division. This is one of the values of x : x-1=0, x=1 (2.) After division, you will be left with x2-x-6=0 (3.) You then use the quadratic formula to find the remaining values of x.
[-b+-(b2-4ac)]/(2a) (4.) Adding from step (1.), the answer is x = 1, 3, -2
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x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
IMPOSSIBLE
No.
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
It is x = -5